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Statement 1 is insufficient because Z could be 1 or -1. Let's say n is 2. 1^2 = 1 and (-1)^2 = 1

Statement 2 is insufficient because if n = 0, then Z could be one of many numbers, such as 1 or 2. If Z = 1, 1^0 = 1. If Z = 2, 2^0 = 1. Any non-zero number raised to 0 equals 1.

Statements 1 and 2 combined are sufficient because with statement 1, we know Z is either 1 or -1 and with statement 2 we know Z is greater than 0. So Z must be 1.
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Re: If z^n = 1, what is the value of z? [#permalink]

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11 Jan 2012, 14:47

Rephrase: The only possibilities here are Z^0 = 1, where Z is any integer. Also, Z = 1 and n is any integer, including 0.

1. n!=0. This means that Z=1 and n=1 or Z=-1 and n=2. insuff 2. Z>0. This means that Z could be anything positive and n=0. insuff

Together, Z=positive. For the stem to be satisfied, Z has to be 1 regardless of value of n. Suff.
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DS - If negative answer only, still sufficient. No need to find exact solution. PS - Always look at the answers first CR - Read the question stem first, hunt for conclusion SC - Meaning first, Grammar second RC - Mentally connect paragraphs as you proceed. Short = 2min, Long = 3-4 min

Re: If z^n = 1, what is the value of z? [#permalink]

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11 Jan 2012, 19:48

First rephrase, the value of z^n = 1 in the following three situations: i)Z is anything, and n is 0 ii)Z is -1 or 1 and n is even iii)z is 1 and n is odd.

a) this gets rid of the first option, but z can still be -1 or 1 - Not Sufficient b) No information about n, so z could be 1 but it could also be any other positive number with n = 0.

Together only the third option is left; n is not zero, and z is 1. so C

Zero raised to any power is zero and any number raised to the power of 0 equals one? Is that the rule of it is reversed?

I'm not sure understand the red part in your post above.

If z^n = 1, what is the value of z?

(1) n is a non zero integer --> \(1^{any \ integer}=1\) and also \((-1)^{even}=1\), so \(z\) can be 1 or -1. Not sufficient.

(2) z > 0 --> any nonzero number to the power of 0 is 1, so if \(n=0\) then \(z\) can be any non-zero number (any positive number in our case as given that \(z>0\)). Not sufficient.

(1)+(2) \(n\) is a nonzero integer and \(z>0\) implies that \(z\) can equal to 1 only. Sufficient.

Re: If z^n = 1, what is the value of z? [#permalink]

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07 Jan 2015, 16:13

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Zero raised to any power is zero and any number raised to the power of 0 equals one? Is that the rule of it is reversed?

This is not a difficult question by itself, but clarity of approach matters a lot in getting it right. The low accuracy for this question suggests that most students could not think through this question clearly.

At eGMAT, we strongly advocate that in DS Questions,the student should first analyze the question statement thoroughly and only then move on to analyzing the two statements. You'll see how elegantly this question will simplify with this approach.

We are given that z^n = 1. So, what cases are possible for the value of z and n?

Case 1: z = 1; n has any integral value Case 2: z = -1; n is an even integer Case 3: z has any non-zero value; n = 0

Please note that only after this analysis are we going to the first Statement.

As per the first statement, n is a non-zero integer This rules out Case 3. However, this still leaves out Case 1 and 2. So, z can either be equal to 1 or z can be equal to -1. So, Statement 1 alone is not sufficient.

As per the second statement, z > 0 This rules out Case 2. However, Case 1 and 3 still remain. Again, we have not been able to determine a unique value of z. So, Statement 2 alone is not sufficient either.

Combining both the Statements, From Statement 1, z could either be 1 or -1 From Statement 2, z > 0 Therefore, only possible value of z is 1.

Thus, by combining both the statements together, we have been able to determine a unique value of z. So, the correct answer is Choice C.

Takeaway: The correct answer is only a byproduct of a clear approach.

Re: If z^n = 1, what is the value of z? [#permalink]

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21 Mar 2015, 21:11

Bunuel wrote:

(1) n is a non zero integer --> \(1^{any \ integer}=1\) and also \((-1)^{even}=1\), so \(z\) can be 1 or -1. Not sufficient.

(2) z > 0 --> any nonzero number to the power of 0 is 1, so if \(n=0\) then \(z\) can be any non-zero number (any positive number in our case as given that \(z>0\)). Not sufficient.

(1)+(2) \(n\) is a nonzero integer and \(z>0\) implies that \(z\) can equal to 1 only. Sufficient.

Answer: C.

Can we take \((\sqrt{1})^2\) as a plug in value to check these statements..

(1) n is a non zero integer --> \(1^{any \ integer}=1\) and also \((-1)^{even}=1\), so \(z\) can be 1 or -1. Not sufficient.

(2) z > 0 --> any nonzero number to the power of 0 is 1, so if \(n=0\) then \(z\) can be any non-zero number (any positive number in our case as given that \(z>0\)). Not sufficient.

(1)+(2) \(n\) is a nonzero integer and \(z>0\) implies that \(z\) can equal to 1 only. Sufficient.

Answer: C.

Can we take \((\sqrt{1})^2\) as a plug in value to check these statements..

\(\sqrt{1}=1\), so are you asking whether we can plug 1 for n? Well, yes we can...
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Re: If z^n = 1, what is the value of z? [#permalink]

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22 Sep 2015, 00:06

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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\(\sqrt{1}=1\), so are you asking whether we can plug 1 for n? Well, yes we can...

Oh.. ya.. I forgot that the square root of a perfect number is always +ve.

\(\sqrt{36}\) = 6 (not -6)

So \(\sqrt{1}\) = 1 (not -1)

I had +/- 1 in my head while combining statements I and II together.

Thanks for your clarification..

Any even root from any postie number is positive.

Apologies if I am asking a stupid question but I re-phrased the question stem "If \(z^n = 1\), what is the value of z" to "If \(z = 1^(^1^/^n^)\)", what is the value of z" and after doing this, statement 1 looks sufficient to answer the question. For any non-zero integer value of n, z will always be 1. Please let me know where am I making a mistake? Thanks in advance!

Re: If z^n = 1, what is the value of z? [#permalink]

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16 Oct 2016, 11:59

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If z^n = 1, what is the value of z? [#permalink]

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16 Oct 2016, 15:51

Hi Suhasancd,

There is no stupid question in the GMAT -- just concepts that need to be reviewed. We can't translate If z^n = 1, what is the value of z" to If z = 1^(^1^/^n^), what is the value of z. The only way to do so would be by using the logarithm, which is not tested on the GMAT.
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Re: If z^n = 1, what is the value of z?
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16 Oct 2016, 15:51

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