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is 1/p > r/(r^2 + 2) 1) p = r 2) r > 0 I got A, but

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Director
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is 1/p > r/(r^2 + 2) 1) p = r 2) r > 0 I got A, but [#permalink] New post 25 Feb 2008, 09:06
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is 1/p > r/(r^2 + 2)

1) p = r
2) r > 0

I got A, but it's not the right answer.
1 KUDOS received
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Concentration: Entrepreneurship, Other
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Re: DS p and r [#permalink] New post 25 Feb 2008, 09:13
1
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C

1) p = r. for 1: 1>1/3 thrue; for -1: -1>-1/3 false. insufficient.
2) r > 0. Nothing about p. insufficient.

1&2) 1/r>r/(r^2+2)
using (r>0) : 1>\frac{r^2}{r^2+2} ==> 1>1 -\frac{2}{r^2+2} ==> \frac{2}{r^2+2}>0 true. sufficient
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Director
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Joined: 20 Aug 2007
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Location: Chicago
Schools: Chicago Booth 2011
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Kudos [?]: 78 [0], given: 1

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Re: DS p and r [#permalink] New post 25 Feb 2008, 10:55
Well done, kudos :)
Re: DS p and r   [#permalink] 25 Feb 2008, 10:55
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