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Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
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So we can safely forget the 0’s in the 200 and 100. since Machine A,B and C all made the same widget.

Rate of A (Ra) =2/14
Rate of B (Rb) =2/7=4/14
Rate of C (Rc)= 2/2=14/14

Total Rate (Rt) = R(a)+R(b)+R(c)
Total Rate (Rt) =2/14+4/14+14/14
(Rt) =20/14=10/7
Total work =1
R•T=W —> (10/7)•T=1 —> T=7/10(hrs)
T=7/10•60mins =42 mins

Answer B

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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
Bunuel wrote:
Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes

200= a14 = b7 = c2
We have to find k
(a+b+c)k = 100, replace the values of a,b and c.
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
Arvind42 wrote:
Bunuel wrote:
Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes


Logically C alone can make 100 widgets in 1 hour so C,B and E is eliminated.

Rate is 200/14,200/7 and 200/2 respectively. So if they work together then they can 200/14 + 200/7 + 200/2 = 2000/14 that is produce 2000 widgets in 14 hours/840 minutes. So 1000 widgets take 840*100/2000 = 42 IMO B


I liked your approach of eliminating 3 options straight up. It shows the confidence even during the exam
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
Expert Reply

Solution


Given:
    • Machine A can make 200 widgets in 14 hours
    • Machine B can make 200 widgets in 7 hours
    • Machine C can make 200 widgets in 2 hours

To find:
    • Time taken by them to complete 100 widgets when working together

Approach and Working Out:
    • A + B + C can together make 200 widgets in \(1/(\frac{1}{14} + \frac{1}{7} + \frac{1}{2}) = \frac{14}{10} = \frac{7}{5}\) hours
    • Therefore, they take \(\frac{1}{2} * \frac{7}{5} = \frac{7}{10}\) hours = 42 minutes to make 100 widgets

Hence, the correct answer is Option B.

Answer: B

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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
Bunuel wrote:
Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes


for every 200 widgets combined rate ; 1/14+1/7+1/2 = 10/14 and total time ; 14/10 ; for half widgets ie 100 ; 14/10 * 1/2 = 7/10 hrs
in mins ; 7 * 60/10 ; 42 mins
IMO b
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
Bunuel wrote:
Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes

A-100 pins-7 hrs
B-100 pins-3.5hrs
C-100 pins- 1 hr

1/A+1/B+1/C=50/35

hence time is 35/50*60=42 mins
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
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Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes

Solution

Work(W) = Rate(R) * Time (T)

Work ( W) is given to be 200 for A, B, and C... lets keep it the way..

Rate for A = A's work / A's Time (from the formula)
= 200/14

Similarly B's Rate = 200/7

and

C's rate = 200/2 respectively.

Their collective rate (lets say K) will be A's rate + B's rate + C's rate. (as rates can be added)

Therefore,
K = 200/14 + 200/7 + 200/2 = 2000/14

they produce 2000 widgets in 14 hours

Now we're given a new work of 100 midgets..
which we can simply put in the formula
W = R * T
Rate we know for collective is 2000/14
and W = 100
therefore,
Time = 100/2000/14 = 100*14/2000 = 14/20

This will be in hours, now multiply it by 60 to get the value in minutes= 14*60/20 = 14*3 = 42

to get to answer option 42 mins (B)
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
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Expert Reply
Bunuel wrote:
Machine A can make 200 widgets in 14 hours, Machine B can make 200 widgets in 7 hours, and Machine C can make 200 widgets in 2 hours. How long does it take them to complete 100 widgets when working together?

A. 32 minutes
B. 42 minutes
C. 84 minutes
D. 90 minutes
E. 96 minutes



The rate for Machine A is 200/14, for Machine B 200/7, and for Machine C 200/2. Thus, we can create the following combined rate:

200/14 + 200/7 + 200/2

200/14 + 400/14 + 1400/14 = 2000/14

So the time to completed 100 widgets is:

100/(2000/14) = 100 x 14/2000 = 14/20 = 42/60 hours = 42 minutes

Answer: B
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
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Re: Machine A can make 200 widgets in 14 hours, Machine B can make 200 wid [#permalink]
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