aimtoteach wrote:
Harley1980 wrote:
When integer A is divided by 79, remainder is X and when integer B is divided by 79, remainder is Y. What is X * Y?
1) When A + B is divided by 79, remainder is 18
2) When A * B is divided by 79, remainder is 77
Hi,
I used simpler numbers (11, 19, 4, 8 and divisor as 3) to work up examples and arrived at the correct answer.
Could you please help me with the properties
Thanks,
aimtoteach
Hello aimtoteach.
When we have task about division different numbers on the same divisor we can sum or multiple the equations. For example
"When 7 divided by 5 , remainder is 2 and when 11 divided by 5 , remainder is 1" We can write this information in such way:
\(7=5∗X+2\)
\(11=5∗Y+1\)
if we sum this equations we received such result
\(7+11=5∗Z+(2+1)\) so \(18 / 5\) give us remainder 3
of if we multiple this equations we received:
\(7∗11=5∗R+2\) so \(77 / 5\) give us remainder 2
In our task we can write this phrase "When integer A is divided by 79, remainder is X and when integer B is divided by 79, remainder is Y" in such way:
\(A=79s+X\)
\(B=79r+Y\)
and when we sum this equations we received
\(A+B=79z+(X+Y)\)
and from first statement we know that "When A + B is divided by 79, remainder is 18"
So we can make infer that \(X+Y=18\). But from this inforamation we can't make infer about what X*Y equal because X+Y = 18 can give us more than one combinations: 1+17; 2+16 etc.
Insufficient
and when we multiple this equations we received
\(A∗B=79z+(X∗Y)\)
and from second statement we know that "When A * B is divided by 79, remainder is 77"
So we can make infer that X∗Y=77 and we find answer that we need
Sufficient.Update (thanks to
smyarga for noticing mistake in answer):
This is insufficient statement. Because when we add or multiply such equations, we should take into account that X+Y or X*Y can give bigger result than divisor. And in such cases we should subtract divisor from this result and only after this it will give us correct remainder.
In our task there is possible such variant:
\(A=83\) and \(X=4\); when \(83\) divided by \(79\) there is remainder \(4\)
\(B=118\) and \(Y=39\); when \(118\) diveded by \(79\) there is remainder \(39\)
and when we multiple \(A\) and \(B\) we received \(9794\) and divided by \(79\) we will have remainder \(77\) but \(X*Y=156\) and this product not equal to remainder
So information in second statement is not sufficient and we need first statement too.
And answer is C.