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The function f is defined for all positive integers n by the

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Manager
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The function f is defined for all positive integers n by the [#permalink] New post 28 Apr 2006, 22:05
The function f is defined for all positive integers n by the following rule:
f(n) is the number of positive integers each of which is less than n
and has no positive factor in common with n other than 1.if p is any prime number then f(p) =

a. p-1
b. p-2
c. (p+1)/2
d. (p-1)/2
e. 2

please help

OA to follow
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 [#permalink] New post 28 Apr 2006, 22:30
I'll take a shot at this and take B

All prime numbers have 7 integers less than itself and have no common factor with the prime other than 1

2 ==> 1 (1 is less than 2 but it has a common factor with 2) so 2-2 = 0

3 ==> 1, 2 (only 2 is less than 3 that have no common factor with 3 other than 1) so 3 - 2 = 1

5 ==> 1, 2, 3, 4 (only 2, 3, 4 are less than 5 that have no common factor with 5 other than 1) so 5-2 = 3
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 [#permalink] New post 29 Apr 2006, 04:23
Agreed with B!

f(P)= number of items in the set {2,3,4,....(n-1)}
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 [#permalink] New post 29 Apr 2006, 09:13
Does the expression 'other than 1' means we ought to exclude 1?

Can this expression also mean the numbers are co prime to each other, in which case 1 is an acceptable common factor between n and any number less than it?

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 [#permalink] New post 06 May 2006, 16:52
Dinesh are you sure of the OA ? I got this question from gmatprep and the offical answer is A and not B .

Please confirm . thanks.
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 [#permalink] New post 09 May 2006, 04:05
I've seen this q before and the OA is A, though I get B.
can someone pls explain how it can be A?
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 [#permalink] New post 09 May 2006, 04:08
the number 1 has no positive factor in common with n other than 1.
so A it is.

Tricky. I thought B first too...
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 [#permalink] New post 09 May 2006, 04:14
kook44 wrote:
the number 1 has no positive factor in common with n other than 1.
so A it is.

Tricky. I thought B first too...


Oh yes, thar's it !! Tricky question.
  [#permalink] 09 May 2006, 04:14
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