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Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more

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Dallas Jockey
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Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   Updated on: 03 Jan 2021, 06:37
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Question Stats:

70% (02:21) correct 30% (03:08) wrong based on 311 sessions
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Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5

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I have formed the following algebric equations for the above, but I can't seem to get to the answer.

A + B = p

B = A + 10

C = p/4 + A


However, if I use actual numbers and plug the answer, the question can be solved. What am I missing?

Thanks
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Official Answer
B

Originally posted by Dallas Jockey on 15 Jul 2006, 12:44.
Last edited by Bunuel on 03 Jan 2021, 06:37, edited 5 times in total.
Renamed the topic, edited the question and added the OA.
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Dallas Jockey
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   16 Jul 2006, 10:42
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guys, the correct answer is B

I know the question is poorly written - but hey..i copied it from a 'reputed' GMAT prep book.

But the trick is the word "weighs"....meaning only cubby weighS P/4 + A

Read the question as (Brian + Andrea)'s dog, cubby weighs...

And thanks for the help
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bmwhype2
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   17 Feb 2008, 15:50
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pretty straightforward.

a + b = p

b = a + 10

c = p/4 + a

there is no b in the choices. this means we have to get rid of it.

a+ (a+10) = p
2a = p -10
a = p/2 - 5

c= p/4 + a
c= p/4 + p/2 - 5
c = p/4 + 2p/4 - 5
c = 3p/4 - 5
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   13 Jul 2013, 02:26
Two interpretation:
1. Cubby belongs to Andrea: answer is p/4-10
2. Cubby belongs to A&B: answer is B
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   13 Jul 2013, 02:50
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nson wrote:
Two interpretation:
1. Cubby belongs to Andrea: answer is p/4-10
2. Cubby belongs to A&B: answer is B


There is only one correct interpretation.

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5

Together, Andrea and Brian weigh p pounds --> A + B = p.
Brian weighs 10 pounds more than Andrea --> B = A + 10 --> A + (A + 10) = p --> A = (p - 10)/2 = p/2 - 5.
Brian and Andrea's dog, Cubby, weighS p/4 pounds more than Andrea --> C = A + p/4 = (p/2 - 5) + p/4 = 3p/4 -5. Singular verb "weighS" cannot refer to Brian and Cubby, it refers to Cubby only.

Answer: B.

Hope it's clear.
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   23 Sep 2013, 23:04
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Bunuel wrote:
nson wrote:
Two interpretation:
1. Cubby belongs to Andrea: answer is p/4-10
2. Cubby belongs to A&B: answer is B


There is only one correct interpretation.

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5

Together, Andrea and Brian weigh p pounds --> A + B = p.
Brian weighs 10 pounds more than Andrea --> B = A + 10 --> A + (A + 10) = p --> A = (p - 10)/2 = p/2 - 5.
Brian and Andrea's dog, Cubby, weighS p/4 pounds more than Andrea --> C = A + p/4 = (p/2 - 5) + p/4 = 3p/4 -5. Singular verb "weighS" cannot refer to Brian and Cubby, it refers to Cubby only.

Answer: B.

Hope it's clear.


Hi Bunuel,

I understand the Solution. But i have a small doubt

Brian and Andrea's dog, Cubby, weighS p/4 pounds more than Andrea --> C = A + p/4
Then how should be it stated in the question for construction like this ? C= A + (Ap) /4

Please help me

Thanks in Advance,
Rrsnathan.
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   24 Sep 2013, 07:27
Expert Reply
rrsnathan wrote:
Bunuel wrote:
nson wrote:
Two interpretation:
1. Cubby belongs to Andrea: answer is p/4-10
2. Cubby belongs to A&B: answer is B


There is only one correct interpretation.

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5

Together, Andrea and Brian weigh p pounds --> A + B = p.
Brian weighs 10 pounds more than Andrea --> B = A + 10 --> A + (A + 10) = p --> A = (p - 10)/2 = p/2 - 5.
Brian and Andrea's dog, Cubby, weighS p/4 pounds more than Andrea --> C = A + p/4 = (p/2 - 5) + p/4 = 3p/4 -5. Singular verb "weighS" cannot refer to Brian and Cubby, it refers to Cubby only.

Answer: B.

Hope it's clear.


Hi Bunuel,

I understand the Solution. But i have a small doubt

Brian and Andrea's dog, Cubby, weighS p/4 pounds more than Andrea --> C = A + p/4
Then how should be it stated in the question for construction like this ? C= A + (Ap) /4

Please help me

Thanks in Advance,
Rrsnathan.


Strange construction...

C= A + (Ap) /4 = A(1+p/4)

Brian and Andrea's dog, Cubby, weighS (1+p/4) times as much as Andrea.
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink] New post   23 Feb 2022, 14:35
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Re: Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more [#permalink]
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