What is the greatest possible area of triangular region with : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 17 Jan 2017, 18:09

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the greatest possible area of triangular region with

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 15 Nov 2006
Posts: 219
Location: Ohio
Followers: 1

Kudos [?]: 53 [0], given: 0

What is the greatest possible area of triangular region with [#permalink]

### Show Tags

04 Apr 2007, 15:52
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the greatest possible area of triangular region with one vertex at the center of the a circle with radius 1 and the other two vertices on the circle?
A)sqrt3/4
B)1/2
C)pi/4
D)1
E)sqrt2
Manager
Joined: 15 Nov 2006
Posts: 219
Location: Ohio
Followers: 1

Kudos [?]: 53 [0], given: 0

### Show Tags

04 Apr 2007, 16:59
OA is B.

Thanks!

Nitin
Manager
Joined: 15 Nov 2006
Posts: 219
Location: Ohio
Followers: 1

Kudos [?]: 53 [0], given: 0

### Show Tags

04 Apr 2007, 17:12
Trvikram,

How did you figure out that this would be the triangle with largest area?

thanks!
Intern
Joined: 01 Feb 2007
Posts: 25
Followers: 0

Kudos [?]: 2 [0], given: 0

Answer is 1/2 [#permalink]

### Show Tags

04 Apr 2007, 19:26
The measure of an inscrbed angle is 1/2 of the measure of the intercepted arc. This is a theorem. An inscribed angle is an angle with its vertex on the circle and the sides of it contain chords of the circle.

The maximum inscribed angle that can be formed in this instance is 90 degrees since the maximum angle of the arc that can be formed is 180 degrees (A semi-circle). By this theorem the inscribed angle becomes 90 degrees which forms the height of the triangle. Now apply the formula 1/2 * b * h which gives us 1/2.
Answer is 1/2   [#permalink] 04 Apr 2007, 19:26
Display posts from previous: Sort by

# What is the greatest possible area of triangular region with

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.