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Working at their respective constant rates, machine A makes [#permalink]
09 Mar 2011, 14:03
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Difficulty:
95% (hard)
Question Stats:
42% (02:22) correct
58% (01:40) wrong based on 146 sessions
Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 100 copies in 15 minutes. If a number of x machine A and a number of y machine B work simultaneously at their respective rates for 2 hours, what is the total number of copies that they will produce?
Re: Working at their respective constant rates, machine A makes [#permalink]
09 Mar 2011, 16:00
banksy wrote:
268. Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 100 copies in 15 minutes. If a number of x machine A and a number of y machine B work simultaneously at their respective rates for 2 hours, what is the total number of copies that they will produce? (1) x = y. (2) 5x + 4y = 90.
can't find the the total copies that they will produce without knowing the value of x and y. So with (1) and (2), it is sufficient to find values. Answer C.
Re: Working at their respective constant rates, machine A makes [#permalink]
09 Mar 2011, 22:56
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banksy wrote:
268. Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 100 copies in 15 minutes. If a number of x machine A and a number of y machine B work simultaneously at their respective rates for 2 hours, what is the total number of copies that they will produce? (1) x = y. (2) 5x + 4y = 90.
Rate of Machine A is 100/12 copies per minute and that of Machine Y is 100/15 copies per minute.
When x number of A machines and y number of B machines work simultaneously at their respective rates for 2 hours (120 minutes), they will produce \(120*((100/12)*x+(100/15)*y)\)copies
\(120*((100/12)*x+(100/15)*y)\) on simplification becomes \(200*(5x+4y)\)
Statement 1 says \(x=y\), which doesn't help us get the exact numbers, so insufficient
Statement 2 says \(5x+4y = 90\), we cant solve for x and y from this, but all we need to answer the question is value of 5x+4y which we get from this statement, so sufficient.
Re: Working at their respective constant rates, machine A makes [#permalink]
09 Mar 2011, 23:11
Mongolia2HBS wrote:
banksy wrote:
268. Working at their respective constant rates, machine A makes 100 copies in 12 minutes and machine B makes 100 copies in 15 minutes. If a number of x machine A and a number of y machine B work simultaneously at their respective rates for 2 hours, what is the total number of copies that they will produce? (1) x = y. (2) 5x + 4y = 90.
can't find the the total copies that they will produce without knowing the value of x and y. So with (1) and (2), it is sufficient to find values. Answer C.
subhashghosh wrote:
(1) is clearly insufficient.
For (2), several answers are possible:
5 * 14 + 4 * 5 = 90
5 * 10 + 4 * 8 = 90
But (1) and (2) together give x = y = 10, so answer is C
Guys, we are not concerned here with exact values of x and y. All we need to find is the total number of copies the machines working together would produce. So, anything that gives us their combined relationship is sufficient. Statement 2 effectively is telling us about that relationship.
So, statement B is sufficient to answer the given question.
Irrespective of whatever value x and y individually may have, as long as 5x+4y is 90, the number of pages they will produce would remain 200*90
We can easily check the same by putting different values for x and y.
Re: Working at their respective constant rates, machine A makes [#permalink]
15 Dec 2014, 09:50
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Re: Working at their respective constant rates, machine A makes [#permalink]
29 Dec 2015, 09:50
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