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# You have 4 jars of pills. Each pill is a certain weight,

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You have 4 jars of pills. Each pill is a certain weight, [#permalink]  10 Sep 2008, 20:30
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?
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Re: Fun Math [#permalink]  10 Sep 2008, 21:10
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?

each pill weight =w
contaminated pill weight=w+1

Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.
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SVP
Joined: 29 Aug 2007
Posts: 2493
Followers: 59

Kudos [?]: 576 [0], given: 19

Re: Fun Math [#permalink]  10 Sep 2008, 21:23
x2suresh wrote:
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?

each pill weight =w
contaminated pill weight=w+1

Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.

you can find anywhere else. just google:

try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?
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Re: Fun Math [#permalink]  10 Sep 2008, 22:07
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?[/quote]

Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.
SVP
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Posts: 1824
Location: New York
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Kudos [?]: 562 [0], given: 5

Re: Fun Math [#permalink]  11 Sep 2008, 04:06
scthakur wrote:
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?

Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.[/quote]

agreed.

These questions... sound similar to sankunthala devi puzzles..
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Re: Fun Math   [#permalink] 11 Sep 2008, 04:06
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