Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A list contains twenty integers, not necessarily distinct. D [#permalink]
17 Jun 2014, 09:42

2

This post received KUDOS

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

34% (02:08) correct
66% (01:01) wrong based on 50 sessions

A list contains twenty integers, not necessarily distinct. Does the list contain at least two consecutive integers?

(1) If any single value in the list is increased by 1, the number of different values in the list does not change.

(2) At least one value occurs more than once in the list.

A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B) Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D) EACH statement ALONE is sufficient. E) Statement (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data are needed.

Re: A list contains twenty integers, not necessarily distinct. D [#permalink]
17 Jun 2014, 10:20

2

This post received KUDOS

ill reduce the numbers to 5

(1) If any single value in the list is increased by 1, the number of different values in the list does not change. suppose the numbers are 1, 3, 5, 7, 9 a) If we increase any of the above numbers by 1 then the number of distinct value does not change. The values are not consecutive.

b) suppose the numbers are 2, 2, 3, 6, 9 If we increase the value of 2 by 1 then the list will become 2, 3, 3, 6, 9 The number of distinct values still remains same. But the numbers are consecutive. For this to happen two numbers need to be consecutive.

Two different answers, therefore 1 is not sufficient.

(2) At least one value occurs more than once in the list. Clearly insufficient.

Both together will give us condition b discussed above. Hence both are sufficient together.

Ans: C

Last edited by shank001 on 18 Jun 2014, 10:59, edited 1 time in total.

Re: A list contains twenty integers, not necessarily distinct. D [#permalink]
18 Jun 2014, 02:24

1

This post received KUDOS

Expert's post

1

This post was BOOKMARKED

honchos wrote:

A list contains twenty integers, not necessarily distinct. Does the list contain at least two consecutive integers?

(1) If any single value in the list is increased by 1, the number of different values in the list does not change.

(2) At least one value occurs more than once in the list.

Even though shank001 has provided a great solution above, I would like to give my thoughts on this question.

Here, it is easy to fall for statement 1. At first, it seems as if statement 1 is sufficient. Say, if any single value is increased by 1, it doesn't match any other value already there in the list, it means that there are no consecutive integers. What you might forget that when you increase a number by 1 is that one distinct integer is getting wiped out and another is taking its place!

But your statement 2 should give you a hint. Since statement 1 doesn't tell you that all values are distinct, statement 2 should make you think that you need to consider the case where one value occurs more than once in the list. In that case, is it possible that number of different values in the list does not change even though there is a pair of consecutive integers?

Say 5, 5, 6, 9, 20, 50, 57, 87 ... etc Now if you increase 5 by 1, you get 6 and number of distinct integers stays the same! In this case, if there are no consecutive integers, the number of distinct integers will increase. Hence if the numbers are not all distinct and the number of distinct numbers needs to stay same, there must be a pair of consecutive integers.

This tells you that statement 1 is not sufficient alone and you need both statements to answer the question.

Takeaway - Just as when you get an easy (C), you must check whether the answer could be (A) or (B), when you feel that the answer is (A) or (B), you might want to check whether the other statement is necessary to establish any one statement alone. _________________

Re: A list contains twenty integers, not necessarily distinct. D [#permalink]
18 Jun 2014, 11:02

VeritasPrepKarishma wrote:

honchos wrote:

A list contains twenty integers, not necessarily distinct. Does the list contain at least two consecutive integers?

(1) If any single value in the list is increased by 1, the number of different values in the list does not change.

(2) At least one value occurs more than once in the list.

Even though shank001 has provided a great solution above, I would like to give my thoughts on this question.

Here, it is easy to fall for statement 1. At first, it seems as if statement 1 is sufficient. Say, if any single value is increased by 1, it doesn't match any other value already there in the list, it means that there are no consecutive integers. What you might forget that when you increase a number by 1 is that one distinct integer is getting wiped out and another is taking its place!

But your statement 2 should give you a hint. Since statement 1 doesn't tell you that all values are distinct, statement 2 should make you think that you need to consider the case where one value occurs more than once in the list. In that case, is it possible that number of different values in the list does not change even though there is a pair of consecutive integers?

Say 5, 5, 6, 9, 20, 50, 57, 87 ... etc Now if you increase 5 by 1, you get 6 and number of distinct integers stays the same! In this case, if there are no consecutive integers, the number of distinct integers will increase. Hence if the numbers are not all distinct and the number of distinct numbers needs to stay same, there must be a pair of consecutive integers.

This tells you that statement 1 is not sufficient alone and you need both statements to answer the question.

Takeaway - Just as when you get an easy (C), you must check whether the answer could be (A) or (B), when you feel that the answer is (A) or (B), you might want to check whether the other statement is necessary to establish any one statement alone.

Karishma (1) gives YES and NO so Insufficient (2) Insufficient

Even (1) and (2) together Gives yes and NO situation So answer should be E.

from (1) and (2) IF WE INCREASE 3 then we may get consecutive Number, but it is not essential. The condition is of May so (1) and (2) also Gives Yes and No situation hence the answer is E. _________________

Re: A list contains twenty integers, not necessarily distinct. D [#permalink]
18 Jun 2014, 11:16

If we increase 3 to 4, then the first statement is violated - the number of distinct values should remain same after increasing value by 1. To satisfy both stmt one and stmt two, we need to make sure that increase by 1 does not create a new number in the list. this can be achieved only when there are two consecutive numbers on the list.

hope this helps.

honchos wrote:

VeritasPrepKarishma wrote:

honchos wrote:

A list contains twenty integers, not necessarily distinct. Does the list contain at least two consecutive integers?

(1) If any single value in the list is increased by 1, the number of different values in the list does not change.

(2) At least one value occurs more than once in the list.

Even though shank001 has provided a great solution above, I would like to give my thoughts on this question.

Here, it is easy to fall for statement 1. At first, it seems as if statement 1 is sufficient. Say, if any single value is increased by 1, it doesn't match any other value already there in the list, it means that there are no consecutive integers. What you might forget that when you increase a number by 1 is that one distinct integer is getting wiped out and another is taking its place!

But your statement 2 should give you a hint. Since statement 1 doesn't tell you that all values are distinct, statement 2 should make you think that you need to consider the case where one value occurs more than once in the list. In that case, is it possible that number of different values in the list does not change even though there is a pair of consecutive integers?

Say 5, 5, 6, 9, 20, 50, 57, 87 ... etc Now if you increase 5 by 1, you get 6 and number of distinct integers stays the same! In this case, if there are no consecutive integers, the number of distinct integers will increase. Hence if the numbers are not all distinct and the number of distinct numbers needs to stay same, there must be a pair of consecutive integers.

This tells you that statement 1 is not sufficient alone and you need both statements to answer the question.

Takeaway - Just as when you get an easy (C), you must check whether the answer could be (A) or (B), when you feel that the answer is (A) or (B), you might want to check whether the other statement is necessary to establish any one statement alone.

Karishma (1) gives YES and NO so Insufficient (2) Insufficient

Even (1) and (2) together Gives yes and NO situation So answer should be E.

from (1) and (2) IF WE INCREASE 3 then we may get consecutive Number, but it is not essential. The condition is of May so (1) and (2) also Gives Yes and No situation hence the answer is E.

from (1) and (2) IF WE INCREASE 3 then we may get consecutive Number, but it is not essential. The condition is of May so (1) and (2) also Gives Yes and No situation hence the answer is E.

hi lets shorten this set that you have considered. Suppose we have only first 6 elements in the set. i.e . 1,3,3,5,7,9

now number of different elements in the set are 5 (1,3,5,7,9)

if i increase 3 with 1 then number of different element in the set becomes 6 (1,3,4,5,7,9) which violates the statement 1

but if we increase 1,5,7 or 9 with 1, number of different elements remains same. therefore we can safely conclude that we definitely have at least 2 consecutive integers in the set.

from (1) and (2) IF WE INCREASE 3 then we may get consecutive Number, but it is not essential. The condition is of May so (1) and (2) also Gives Yes and No situation hence the answer is E.

Actually the first statement says that if ANY number is increased by 1, the number of distinct values does not change. So the number of distinct values should stay the same for EACH value in the list. So when we increase the 3 by 1, the number of distinct values should not change. Hence the set given by you above is not possible. It must be 1,3,3, 4, 7, 9,11, 13,15,17,19,21,23,25,27,29,31,33,35,37 _________________

from (1) and (2) IF WE INCREASE 3 then we may get consecutive Number, but it is not essential. The condition is of May so (1) and (2) also Gives Yes and No situation hence the answer is E.

Actually the first statement says that if ANY number is increased by 1, the number of distinct values does not change. So the number of distinct values should stay the same for EACH value in the list. So when we increase the 3 by 1, the number of distinct values should not change. Hence the set given by you above is not possible. It must be 1,3,3, 4, 7, 9,11, 13,15,17,19,21,23,25,27,29,31,33,35,37

Right Karishma,

But If I would have seen this question directly on Gmat. I would have opted E.

Karishma any advice, last time when I gave my examination on December 10 2013 I scored Q50 V36, 710.

Any advice How to take somewhere between 750-770 _________________

Re: A list contains twenty integers, not necessarily distinct. D [#permalink]
23 Jun 2014, 00:20

Expert's post

honchos wrote:

Karishma any advice, last time when I gave my examination on December 10 2013 I scored Q50 V36, 710.

Any advice How to take somewhere between 750-770

With a Q50, most of your effort should be directed toward Verbal. Just continue practicing some Quant questions regularly so that your skills don't rust. As far as Verbal is concerned, I assume you are average to above average in 2 question types and quite good in the third one. To hit V42, you need to be quite good in 2 of the three and average to above average in the third. Pick up one of CR, SC and RC and work extra hard in that to ensure that you are very good in at least two of the three question types. _________________