A square picture frame has an outer perimeter of 36 inches and is 1 in

From the figure below , sides of the inner sqaure is 7 inch

So, perimeter of the Inner square is 7*4 = 28 inches...


Answer is (C)

outer perimeter = 36 inches
outer side = 36/4 = 9 inches
subtracting 2 from 9 inches gives value of inner side
inner side = 7 inches
perimeter 4 * 7 = 28 inches
correct answer - C

Perimeter of a square is 4s, outer perimeter = 36 inches, 4s = 36, each outer edge (side) is 36/4 = 9 inches.

The border is 1 inch wide on all sides. To find the inner perimeter of the frame, subtract two inches from each side of the outer perimeter.

Imagine a picture inside the frame that is centered (which is equivalent to the inner perimeter of a frame with a uniform border).

Between the picture and the outside perimeter of the frame, there is +1 inch above, below, to the left, and to the right of the picture. The length of the picture, e.g., has +1 on the left end and +1 on the right end.

So one side of the inner perimeter: (9 - 2) = 7 inches

There are four equal sides (the outside is a square, the border is uniform, therefore the inner perimeter is a square). P = 4s

The inner perimeter, then, in inches, is 4 * 7 = 28

Answer (C)

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.