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At a dinner party

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Manager
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At a dinner party [#permalink] New post 06 Dec 2011, 21:11
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Question Stats:

16% (00:00) correct 83% (00:22) wrong based on 0 sessions
At a dinner party, 5 people are to be seated around a circular table. two seating arrangement are considered different only when the position of the people are different relative to each other. what is the total number of possible seating arrangement for the group?
a.5
b.10
c.24
d.32
e.120
[Reveal] Spoiler: OA
Manager
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Re: At a dinner party [#permalink] New post 06 Dec 2011, 23:38
for 5 people seating arrangement around a circular table = (5-1)!
= 4!
= 4*3*2*1
=24

OA is C
Manager
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Re: At a dinner party [#permalink] New post 06 Dec 2011, 23:44
Anyone can explain carefully???
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Re: At a dinner party [#permalink] New post 07 Dec 2011, 00:22
Hi for n things to make circular arrangement there are (n-1)! ways.
Based on this concept you can solve this question.

How this formula came: say you have n things which you want to arrange circularly.

fix 1 thing first. Now there can be (n-1)! different arrangement of rest things around first.

so total ways of arranging n thins circularly (n-1)!
hope this will help you.
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Re: At a dinner party [#permalink] New post 20 Dec 2011, 13:30
Is the OA A or C? I assume OP is wrong and the answer is C.
Senior Manager
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Re: At a dinner party [#permalink] New post 21 Dec 2011, 13:46
for seating arrangement around a circular table, the permutation formula is

(n-1)!====> (5-1)!=4!=24
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Re: At a dinner party   [#permalink] 21 Dec 2011, 13:46
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