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Seven family members are seated around their circular dinner [#permalink]
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04 Oct 2010, 06:30
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Question Stats:
60% (00:38) correct
40% (00:52) wrong based on 415 sessions
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Seven family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
Seven family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
A. 120 B. 240 C. 360 D. 480 E. 720
Are you sure you got the right OA on this one ?
As I see it : 7 members, and Michael & Bobby sit together. So treat those two like a single person. Now you have to arrange 6 people around a table. This may be done in 5! or 120 ways
The number of ways to arrange Michael & Bobby is 2 (MB or BM).
So net there are 240 ways or B
I don't think this is a GMAT level question, may be a tad too hard
_________________
Seven family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
A. 120 B. 240 C. 360 D. 480 E. 720
Glue Michael and Bobby so that they create one unit, so we would have total of 6 units: {1}{2}{3}{4}{5}{MB} --> # of different arrangements of \(n\) objects around the table (circular arrangements) is is \((n-1)!\), so our 6 objects can be arranged in \((6-1)!=5!\).
On the other hand Michael and Bobby in 2! ways --> total \(5!*2!=240\).
Re: Seven family members are seated around their circular dinner [#permalink]
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21 Sep 2013, 13:27
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Re: Seven family members are seated around their circular dinner [#permalink]
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02 Mar 2015, 10:17
Hello from the GMAT Club BumpBot!
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Re: Seven family members are seated around their circular dinner [#permalink]
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29 Jun 2016, 00:42
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Seven family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?
A. 120 B. 240 C. 360 D. 480 E. 720
Lets consider Michael and Bobby as one individual and fix their position so that all the members do NOT move together while they remain in same order relatively
Now after fixing Michael and Bobby we have 5 other member left to change their positions among themselves which can change positions in 5! ways
but Michael and Bobby and exchange positions between the two in 2! ways'
Hence, Total ways of different arrangements = 5!*2! = 120*2 = 240
Answer: Option B
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60% (00:38) correct
