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keiraria
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Bunuel
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Bunuel
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Can we put all the women in 1 group.
Total will be : 4 men + 1 group of women = 5
To arrange these 5, we will have 5! ways.
Again to group all the women we will have = 4! ways.
Then total ways = 5! X 4!
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Thanks Bunuel.....
I got it and thanks for posting additional links for practice.
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Check out posts on this concept on the blog link given in my signature below.
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we put all the women in 1 group.
Total will be : 4 men + 1 group of 4 women = 5
To arrange these 5 in a circular table, we will have 4! ways.
Again to group all the women we will have = 4! ways.
Then total ways = 4! X 4!
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I found it easiest to answer this question by bundling all the women together.
<W,W,W,W,M,M,M,M> = 8
<[W,W,W,W],M,M,M,M> = 5
Since it's a circular arrangement and shifting everone one way will be the same order, each person shifted accounts for one of the same orders, so basically we just have to remove that.
If there were 5! ways to arrange them in a straight line, there is n!/n ways to arrange them around a circle. You can visualize this by "pinning" one person that everyone is referenced to.
In this case it would be 5!/5 = (5-1)! = 4! ways to arrange all people, then 4! ways to arrange the women in their own group. We don't "pin" any of the women because we already removed the duplicates from the total group.
Total ways = 4!*4!
keiraria
4 couples are seating at a round tables. In how many ways can the 4 women sit together?

A. 4!
B. 5!
C. 4!*4!
D. 5!*4!
E. 5!*5!
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