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Re: Method to solve 3 spheres of dough problem [#permalink]
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tonebeeze wrote:
Is the proper method to solving this problem: (1) find the volume of each sphere (2) add the volumes of the three spheres (3) calculate the radius from the new total volume?

There are three spheres of dough with diameters of 2, 4, and 6 cm. If the three are combined into one large sphere, what is the radius of the large sphere?


Yes, R^3=(2/2)^3+(4/2)^3+(6/2)^3:

\(volume_{sphere}=\frac{4}{3}\pi{r^3}\);

\(volume \ of \ the \ large \ sphere=\frac{4}{3}\pi{1^3}+\frac{4}{3}\pi{2^3}+\frac{4}{3}\pi{3^3}=\frac{4}{3}\pi{(1^3+2^3+3^3)}\);

\(volume \ of \ the \ large \ sphere=\frac{4}{3}\pi{(1^3+2^3+3^3)}=\frac{4}{3}\pi{R^3}\) --> \(R^3=1^3+2^3+3^3=36\).



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