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Re: The price of a certain commodity increased at a rate of [#permalink]
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manalq8 wrote:
The price of a certain commodity increased at a rate of \(X\) % per year between 2000 and 2004. If the price was \(M\) dollars in 2001 and \(N\) dollars in 2003, what was the price in 2002 in terms of \(M\) and \(N\) ?

A. \(\sqrt{MN}\)

B. \(N\sqrt{\frac{N}{M}}\)

C. \(N\sqrt{M}\)

D. \(N\frac{M}{\sqrt{N}}\)

E. \(NM^{\frac{3}{2}}\)


I think that plug-in method is easiest for this problem.

Let the price in 2001 be 100 and the annual rate be 10%. Then:
2001 = 100 = M;
2002 = 110;
2003 = 121 = N;

Now, plug 100 and 121 in the answer choices to see which one gives 110:
A. \(\sqrt{MN}=\sqrt{100*121}=10*11=110\), correct answer right away.

Answer: A.

P.S. For plug-in method it might happen that for some particular numbers more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only.

Hope it helps.
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Re: The price of a certain commodity increased at a rate of [#permalink]
The price of a certain commodity increased at a rate of X % per year between 2000 and 2004. If the price was M dollars in 2001 and N dollars in 2003, what was the price in 2002 in terms of M and N ?

Given:
Price in 2001 : M
Price in 2003 : N
Rate per year: X %

Price in 2002 \(= M ( 1 + X/100)\)........................................(1)
And, Price in 2003: \(N = M( 1 + X/100)^2\)

Or, \((1 + x/100) =\sqrt{(N/M)}\)........(2)

Substituting the value of (2) in (1) above,
Price in 2002 \(= M \sqrt{(N/M)} = \sqrt{MN}\)

Answer: (A)
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Re: The price of a certain commodity increased at a rate of [#permalink]
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manalq8 wrote:
The price of a certain commodity increased at a rate of \(X\) % per year between 2000 and 2004. If the price was \(M\) dollars in 2001 and \(N\) dollars in 2003, what was the price in 2002 in terms of \(M\) and \(N\) ?


A. \(\sqrt{MN}\)

B. \(N\sqrt{\frac{N}{M}}\)

C. \(N\sqrt{M}\)

D. \(N\frac{M}{\sqrt{N}}\)

E. \(NM^{\frac{3}{2}}\)


When no absolute values(or variables pertaining to them) are given, number plugging is the way to go..

Let the Value initially be = 1
and let X% = 100%(in other words..value doubles every year)

values are..
M = 2
N = 8

and we're looking for the value in 2002..which is equal to 4.

Answer (A).
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Re: The price of a certain commodity increased at a rate of [#permalink]
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I think this is the easiest approach here:

2001 - M

2002 - ? (Let it be 'x')

2003 - N

Now according to ques, since the rate of increase is equal both year and the rates should be calculated on the previous year's price,

\(\frac{x-M}{M} * 100= \frac{N-x}{x}*100\)

\(x^2 - Mx = MN - Mx\)

\(x = \sqrt{MN}\)

Answer: A

Hope it helps
+1 Kudos would be nice
:)
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Re: The price of a certain commodity increased at a rate of [#permalink]
Let the original price be $100 in the year 2000.

Let the X% increase be 100% increase which is a multiplier of 2 times.

Year 2000 = 100

Year 2001 = (100) (2) = M

Year 2002 = (100) (2) (2)

Year 2003 = (100) (2) (2) (2) = N

We are looking for the price in the year 2002 in terms of M and N

Target value: (100) (2)^2

If we multiply (M) (N) we get:

(100) (2) (100) (2) (2) (2) =

(100)^2 (2)^4

Then if we take the square root, we get the value in 2002: (100) (2)^2

Answer: *A*

Sqrt(MN)

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Re: The price of a certain commodity increased at a rate of [#permalink]
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