At 12:00 hour a truck left the city A to city B, at a consta

Car started from City B one hour after the truck. So, distance traveled by the truck going at 45 KM/H in this one hour = 45 KM
Distance left to be covered between the car and the truck = 145 KM
Relative speed of the car and truck combined = 100 KM/H + 45 KM/H = 145 KM/H
Time taken to cover this pending distance(D/S) = 145/145 = 1 H

So total time taken = 1H (truck's headstart) + 1H (from prev step) = 2H. So time they met = 12 + 2 = 14.00 Hrs.

Let after t hour they will meet
45t+100(t-1)=190 so, t=2 Ans C

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At 12:00 hour a truck left the city A to city B, at a constant speed of 45 km/h. One hour later, a car left the city B to the city A, along the same road, at a constant speed of 100 km/h. If the distance between A and B is 190 km, at what time will the truck and the car meet each other?

A. 12:40
B. 13:00
C. 14:00
D. 14:40
E. 16:00

==> this is a common velocity question in gmat math test. remember that here, the same time flows the situation.
in case of A truck, it travels at the speed of 45km/h, thus it traveled 45km after 1 hour.
In case of A car, it travels at the speed of 100km/h, and since it started traveling at 13:00, we have 45+45T+100T=190.(It's not the separate t1, t2 here because the same time flows for both the car and truck. Therefore it's just T.)
145T=145, T=1 and therefore at 14:00, the truck and car meet. C is the answer.

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