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Now, \(\frac{71}{72}\) is less but very close to 1, so the answer is B.

Answer: B.

Else, one can notice that since \(\frac{1}{9}\) is less than \(\frac{1}{8}\), thus \(\frac{7}{8}+\frac{1}{9}\) is less than 1. Therefore we can eliminate answer choices C, D, and E. Next, since \(\frac{7}{8}>\frac{3}{4}=\frac{6}{8}\), then answer choice A is also out. So, only answer choice B remains.

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\(\frac{7}{8}+\frac{1}{9}<\frac{7}{8}+\frac{1}{8}=1\) and \(\frac{7}{8}+\frac{1}{9}>\frac{6}{8}=\frac{3}{4}\).

Hence, Answer C. _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: The sum 7/8+1/9 is between [#permalink]
24 Sep 2012, 10:44

1

This post received KUDOS

Expert's post

LCM ----> 71/72 we can notice that 72/72 is 1 so 71/72 must be a bit less than 1 but is impossible to be under 3/4 (0.75). Must be between 3/4 and 1. So B _________________

Now, \(\frac{71}{72}\) is less but very close to 1, so the answer is B.

Answer: B.

Else, one can notice that since \(\frac{1}{9}\) is less than \(\frac{1}{8}\), thus \(\frac{7}{8}+\frac{1}{9}\) is less than 1. Therefore we can eliminate answer choices C, D, and E. Next, since \(\frac{7}{8}>\frac{3}{4}=\frac{6}{8}\), then answer choice A is also out. So, only answer choice B remains.

Answer: B.

Kudos points given to everyone with correct solution. Let me know if I missed someone. _________________