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Re: What is the remainder when 43^43+ 33^33 is divided by 10? [#permalink]
Understood now.. initially i was confused.. thanks
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Re: What is the remainder when 43^43+ 33^33 is divided by 10? [#permalink]
undersood!! thanks alot!
appreciated! :)
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Re: What is the remainder when 43^43+ 33^33 is divided by 10? [#permalink]
Thanks for the explaination Bunuel
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Re: What is the remainder when 43^43+ 33^33 is divided by 10? [#permalink]
The question says what is the remainder when divided by \(10\)?
I know that the unit digit remainder is \(0\) as sum of remainders is \(7+3=10\) but when divided by \(10\), shouldn't it be some other digit after dividing the number by \(10\) (actually \(10th\) digit remainder in this case)?

Let's suppose that last 2-digits for \(43^{43}\) are \(27\) and for \(33^{33}\) are \(33\) then the last 2-digits of the sum would be \(60\) and when divided by \(10\) it gives \(\frac{60}{10}=6\) as a remainder (not essentially \(6\), it can be any \(10th\) digit remainder).
Am I right or not?? Any expert??
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Re: What is the remainder when 43^43+ 33^33 is divided by 10? [#permalink]
HI,

Could we do the following?

last digit of 43^43 = last digit of 43^(10*4+3)= last digit of 43^3=7

last digit of 33^33= last digit of 33^(10*3+3) = last digit of 33^3= 7

If not, what are the rules to the break down the power?

Thanks
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Re: What is the remainder when 43^43+ 33^33 is divided by 10 [#permalink]
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Re: What is the remainder when 43^43+ 33^33 is divided by 10 [#permalink]
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