Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Helpful Geometry formula sheet: http://gmatclub.com/forum/best-geometry-93676.html I hope these will help to understand the basic concepts & strategies. Please Click ON KUDOS Button.

The option is D, Each statement alone is sufficient Simplifying statement , we get 2x(1-x) Now in option A, we can take 4 as common so the statement becomes 2.4(y+1)(1-4y-4) which is definitely divisible by 4, In option B, we can take 2 common same way, which when multiplied by 2 already in statement gives 4 as common which is definitely divisible by 4 , Hence each statement alone in sufficient

if x is a positive integer, is \(x^3 - 3x^2 + 2x\) divisible by 4? 1. x = 4y + 4, where y is an integer

2. x = 2z + 2, where z is an integer

i need some clarification about B

please guide me... _________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

Now i got it Thanks Anyway i committed a mistake in the steps.... _________________

WarLocK _____________________________________________________________________________ The War is oNNNNNNNNNNNNN for 720+ see my Test exp here http://gmatclub.com/forum/my-test-experience-111610.html do not hesitate me giving kudos if you like my post.

Re: is x^3 - 3x^2 + 2x divisible by 4 [#permalink]

Show Tags

03 Jul 2011, 11:26

IMO D: x^3 - 3x^2 + 2x = x(x^2-3x+2) = x(x-2)(x-1) Condition 1: x = 4y + 4, where y is an integer x = 4(y+1) If we put x = 4(y+1) in above eq x(x-2)(x-1) it will be divisible by 4 for all values because x = 4(y+1)

2. x = 2z + 2, where z is an integer x = 2(z+1) if we put x in equation "x(x-2)(x-1)" = 2(z+1)(2z)(2z+1) = 4(z+1)z(2z+1) Again this condition is fine. Hence option D

Re: MGMAT DS: Is the polynomial divisible by 4 [#permalink]

Show Tags

26 Sep 2011, 05:10

+ 1 for D.

Time taken: 52 seconds.

However, I did this question on paper, on second thoughts I realised that this can be done with mental calculations. All we need to know here is that can we have 4 a a common multiple of all components of the equation. _________________

Ifmypostdida dancein your mind, send methe stepsthrough kudos :)

My MBA journey at http://mbadilemma.wordpress.com/

gmatclubot

Re: MGMAT DS: Is the polynomial divisible by 4
[#permalink]
26 Sep 2011, 05:10

Excellent posts dLo saw your blog too..!! Man .. you have got some writing skills. And Just to make an argument = You had such an amazing resume ; i am glad...

So Much $$$ Business school costs a lot. This is obvious, whether you are a full-ride scholarship student or are paying fully out-of-pocket. Aside from the (constantly rising)...

I barely remember taking decent rest in the last 60 hours. It’s been relentless with submissions, birthday celebration, exams, vacating the flat, meeting people before leaving and of...

Rishabh from Gyan one services, India had a one to one interview with me where I shared my experience at IMD till now. http://www.gyanone.com/blog/life-at-imd-interview-with-imd-mba/ ...