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Is IxI = y –z?

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Is IxI = y –z? [#permalink] New post 05 Jun 2011, 05:20
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60% (01:06) correct 40% (00:00) wrong based on 0 sessions
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Re: Is IxI = y –z? [#permalink] New post 05 Jun 2011, 05:37
(1)

x = z - y

So |x| = -x = -(z - y) = y -z only if x is negative

Here we don't know that.


Insufficient

(2)

Insufficient, no information about y and z

(1) + (2)

x is negative, Sufficient.

Answer - C
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Re: Is IxI = y –z? [#permalink] New post 06 Jun 2011, 00:31
another way of looking at this numerical can be,
|x| = positive meaning is y>z being asked here.

a x= z-y means x can be <0 ,= 0 or >0. Hence not sufficient.

b gives no idea of y>z or y<z.

a+b clearly indicated y<z. Hence sufficient.

C it is.
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Re: Is IxI = y –z?   [#permalink] 06 Jun 2011, 00:31
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