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Senior Manager
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Question Stats:
52% (01:43) correct
48% (01:02) wrong based on 1 sessions
Is G < K ? 1. G>K^22. G and K are positive integers Source: GMAT Club Tests - hardest GMAT questions
OE is
S1 is true even if G =1/10 and K=1/10 ; therefore, it is not sufficient.
S2 is obviously insufficient, but together they are sufficient, because then G> K^2 > 1 and this implies G> KMy answer is A When 1. G = 2, K =1 G >K^2 is TRUE, Is G<K - No/False - Suff 2. G = 1/2, K =1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 3. G = 1/2, K =-1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 4. G = 9, K = -2 G >K^2 is TRUE, Is G<K - No/False - Suff 5. G = 1/3, K = -1/3 G >K^2 is TRUE, Is G<K - No/False - Suff 6. G = 1/3, K = 0 G >K^2 is TRUE, Is G<K - No/False - Suff I could not think of an example which will the contradict the answer Am I missing something here  I am completely confused 
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Intern
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Is G < K ? (1) G > K^2 (2) G and K are positive integers. Statement 2: G and K are positive integers. G = 1 and K = 2 => G < K is True. G = 2 and K = 1 => G < K is False. Statement 2 is Clearly not sufficient by itself. This eliminates answers B and D. Remember this statement says G and K are positive and G and K are integers. So, G and K are not fractions. Statement 1: G > K^2 G = 5 and K = 2: 5 > 4, so G > K^2 is True, but G < K is False. G = 1/3 and K = 1/2: 1/3 > 1/4, so G > K^2 is True, but G < K is True. Statement 2 is Clearly not sufficient by itself. This eliminates the answer A. Take Both Statement 1 and 2: G > K^2 and G and K are positive integers. In this case, G and K are position and are integers, so cannot be fractions. Examples: G = 2 and K = 1: 2 > 1, so G > K^2 is True, but G < K is False. G = 5 and K = 2: 5 > 4, so G > K^2 is True, but G < K is False. G = 101 and K = 10: 101 > 100, so G > K^2 is True, but G < K is False. So, the result is consistent and both statement 1 and 2 jointly are sufficient to answer is G < K. The answer choice is C. Do not forget to award me with Kudos+1, if this helps you!! Cheers!!! 
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Livestronger, you were close enough on your number substitution sample #2. But why did you chose the same numbers for both G and K. If you had chosen G = 1/3 and K = 1/2. It satisfies, G > K^2. And clearly answers if G < K. it appears sufficient. But let's try with another substitution. G = 1 and K = 1/2. Again G > K^2 is satisfied. But this time G < K gives you a different answer. Now that's the crucial part(IMHO) of DS. If you can come up with 2 different results for the original question stem, then that particular choice is not Sufficient. Safely POE on that..so A and D are gone. statement #2, seems obvious. It is definitely not sufficient to answer whether G < K. All we know if G > 0 and K > 0 and that they are integers. So B is gone. Now together, they tell a story. Statement 2 affirms us that G and K are not fractions. So our only other contradiction about statement 1 is eliminated. Which leaves us with the fact that if G > 0 and K > 0 and both are integers, then if G > K^2, then always G is > K. HTH...
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CEO
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From statement 1:1. If G = 0.5 and K = 0.7, G > K^2. here G < K. 2. If G = 5 and K = 2, G > K^2. Here G > K. NSF. From statement 2:Either one is greater or smaller than the other. NSF. From Statement 1 and 2:G > K or G is not smaller than K. So Suff.... //C// LiveStronger wrote: Is G< K ? 1. G>K^2 2. G and K are positive integers OA is C
OE is
S1 is true even if G =1/10 and K=1/10 ; therefore, it is not sufficient.
S2 is obviously insufficient, but together they are sufficient, because then G> K^2 > 1 and this implies G> KMy answer is A When 1. G = 2, K =1 G >K^2 is TRUE, Is G<K - No/False - Suff 2. G = 1/2, K =1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 3. G = 1/2, K =-1/2 G >K^2 is TRUE, Is G<K - No/False - Suff 4. G = 9, K = -2 G >K^2 is TRUE, Is G<K - No/False - Suff 5. G = 1/3, K = -1/3 G >K^2 is TRUE, Is G<K - No/False - Suff 6. G = 1/3, K = 0 G >K^2 is TRUE, Is G<K - No/False - Suff I could not think of an example which will the contradict the answer Am I missing something here I am completely confused _________________
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Senior Manager
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masuhari wrote: Livestronger, you were close enough on your number substitution sample #2. But why did you chose the same numbers for both G and K.
If you had chosen G = 1/3 and K = 1/2. It satisfies, G > K^2. And clearly answers if G < K. it appears sufficient. But let's try with another substitution. G = 1 and K = 1/2. Again G > K^2 is satisfied. But this time G < K gives you a different answer. Now that's the crucial part(IMHO) of DS. If you can come up with 2 different results for the original question stem, then that particular choice is not Sufficient. Safely POE on that..so A and D are gone.
statement #2, seems obvious. It is definitely not sufficient to answer whether G < K. All we know if G > 0 and K > 0 and that they are integers. So B is gone.
Now together, they tell a story. Statement 2 affirms us that G and K are not fractions. So our only other contradiction about statement 1 is eliminated. Which leaves us with the fact that if G > 0 and K > 0 and both are integers, then
if G > K^2, then always G is > K.
HTH... Ahhh, I just simply couldn't think of that example  Thanks masuhari and GMAT TIGER
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Manager
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Option C... easy one.... But easy to miss (and mark A incorrectly ) if you do not consider equal fractions for both numbers.
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Manager
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We know that -
is G<K
Opt - A) G>K^2 - alone not sufficient
Opt - B) G and K are +ve integers - alone not sufficient
Combaining together, (two possibilities )
ex) G=3 , K = 10 implies 3>100 = False
G=20 , K = 3 implies 20>9 = True.
So two answers are contradicting each other.
Both A&B together are insufficient.
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CIO
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Hi, The text in red contains an error. If you use information from both statements, you should take such G that follows S1 ( G>K^2). The text in red clearly contradicts S1, so this is not a valid proof. S1+S2 is sufficient, OA is C. I hope it helps you. lnarayanan wrote: We know that -
is G<K
Opt - A) G>K^2 - alone not sufficient
Opt - B) G and K are +ve integers - alone not sufficient
Combaining together, (two possibilities )
ex) G=3 , K = 10 implies 3>100 = False
G=20 , K = 3 implies 20>9 = True.
So two answers are contradicting each other.
Both A&B together are insufficient.
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Manager
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I also got C. But missed to consider 1/2 and 1/3 option 
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it took me so much time, and so many examples to get this one right! Lesson learnt: use fractions when it is NOT given that the numbers are "integers".
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(1) G > K^2 G = 1/2 K = 1/2 G = 1 K = 1/2 Insufficient (2) Not Sufficient (1) + (2) G = 4, K = 1 G = 10, K = 3 Sufficient Answer - C
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Manager
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C is the answer, always consider fractions when nit mentioned integers.
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Put some quick values n check You get C Posted from my mobile device 
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I got C thinking about + and - cases, but I think that will not work and we have to consider fractions.
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Is G < K
1) G > K to power 2
2) G and K are positive integers.
Lets take (1)
Both G and K can be positive or negative integers or even fractions.
(a)If both are positive, when G >K^2, => G > K
(b)If both are negative, when G cannot be greater than K^2 which will then become positive
(c)When both are fractions, we can get all kinds of results.
So, (1) is not enough for us to get an answer - Choce (A) and (D) are ruled out.
Now lets take (2)
Both G and K are postive integers, so G < K only when exact values of G and K are known, which we dont know so (2) is not enough and option (B) is ruled out.
Now its either (C) or (E).
Lets evaluate C -
If both are positive integers and G>K^2, as explained in (a) above, this means that G > K always. Hence (C) is the choice.
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C since (2) eliminates the fractions that were available in (1)
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C, as individual statements will not be sufficient.
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Consider case : g=1/3, k=1/2 therefore k^2 = 1/4. Here g>k^2 but g<k; Hence Answer should be E.
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