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But i have one qstn. Isnt it too much information about triangles from GMAT perspective. Or is it necessary to grab all the concepts put up. _________________

D- Day December 30 2011. Hoping for the happiest new year celebrations !

Bunuel, you posted this in 2009. It's 2012 now and I am finding this so useful. Talk about leaving behind a legacy. you deserve a nice, large, value-saver family pack of Kudos! _________________

If you like it, Kudo it!

"There is no alternative to hard work. If you don't do it now, you'll probably have to do it later. If you didn't need it now, you probably did it earlier. But there is no escaping it."

Yup, I have been going through each section of the Math Book since morning! _________________

If you like it, Kudo it!

"There is no alternative to hard work. If you don't do it now, you'll probably have to do it later. If you didn't need it now, you probably did it earlier. But there is no escaping it."

Has a similar project been done for Verbal? I have Whiplash's CR material. (The one with the pretty cover and ZOMG! ZOMG! ZOMG! written on it). Has somebody put together a similar core-concepts book for Verbal? _________________

If you like it, Kudo it!

"There is no alternative to hard work. If you don't do it now, you'll probably have to do it later. If you didn't need it now, you probably did it earlier. But there is no escaping it."

Small error here I think :"A right triangle inscribed in a circle must have its hypotenuse as the diameter of the circle. The reverse is also true: if the diameter of the circle is also the triangle’s hypotenuse, then that triangle is a right triangle.

Wouldn't it make more sense to say "if the diameter of the circle is one of the sides of a triangle inscribed in a circle, the triangle is a right triangle"? Calling the diameter a hypotenuse suggests that we already know that it's a right triangle.

Does GMAC test trignometry? for example - could we expect such problem?

Solve the triangle below for angle x and then compute the area of the triangle.

Say a triangle ABC with angles A, B and C with opposite sides to these angles a,b, and c respectively. a = 5 inches and b = 3 inches and angle A = 75 degrees find B =?

Well,that's the directory..have seen that already..but they contain the links of all the PS and DS problems submitted in the forum by all the forum members.But actually I was looking for specific Geometry problem set created by experts...like other problems in your signature.So,could you please share any such specific links,if any?

Hello Bunuel, I have downloaded the math book and it is simply amazing. Really awesome power packed PDF! Very helpful, I wish I came across this site much earlier.

I am currently going through Triangles and I have a small doubt regarding Median and angle bisector. In angle bisector section you mentioned that "each point of any angle bisector is equidistant from the sides of the triangle", By extension can I say that the point at which the angle bisector intersects the opposite side is that side's midpoint? And therefore an angle bisector is the median? _________________

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gmatclubot

Re: Math: Triangles
[#permalink]
04 Feb 2014, 08:05

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