Last visit was: 28 Apr 2024, 18:37 It is currently 28 Apr 2024, 18:37

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
User avatar
Manager
Manager
Joined: 03 Jul 2009
Posts: 81
Own Kudos [?]: 430 [40]
Given Kudos: 13
Location: Brazil
 Q50  V35
Send PM
Most Helpful Reply
User avatar
Manager
Manager
Joined: 17 Nov 2011
Status:Employed
Posts: 67
Own Kudos [?]: 433 [7]
Given Kudos: 10
Location: Pakistan
Concentration: International Business, Marketing
GMAT 1: 720 Q49 V40
GPA: 3.2
WE:Business Development (Internet and New Media)
Send PM
General Discussion
VP
VP
Joined: 30 Apr 2008
Posts: 1230
Own Kudos [?]: 951 [1]
Given Kudos: 32
Location: Oklahoma City
Concentration: Life
Schools:Hard Knocks
 Q47  V42
Send PM
User avatar
Current Student
Joined: 20 Jul 2009
Affiliations: ?
Posts: 132
Own Kudos [?]: 73 [0]
Given Kudos: 6
Location: Africa/Europe
Concentration: Entrepreneurship, Finance, Strategy
Schools:Kellogg; Ross ($$); Tuck
 Q48  V38
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
jallenmorris wrote:
A

If the hexagon is a true hexagon and all sides equal, all angles equal, etc, then drawing three lines between the verticies


yes but they did not said that it was a "true one, with all side equal"

Answer should be C.
we can only solve the pb if we know that it is a regular hexagone.
Attachment:
hex.GIF
hex.GIF [ 2.49 KiB | Viewed 12436 times ]
exemple of an hexagone that is not regular...
avatar
Manager
Manager
Joined: 21 Jun 2009
Posts: 94
Own Kudos [?]: 45 [0]
Given Kudos: 1
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
IMO C,

Only the question stem will not suffice that it's a regular hexagon.

1) We dont know yet if its a regular hexagon yet. - NS
2) Says that it is a regular hexagon, but doesn't give us any other info. - NS
1+2) Regular hexagon with each triangle of area 12 . So Area = 12* 6 = 72 square units. Suff
VP
VP
Joined: 30 Apr 2008
Posts: 1230
Own Kudos [?]: 951 [4]
Given Kudos: 32
Location: Oklahoma City
Concentration: Life
Schools:Hard Knocks
 Q47  V42
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
3
Kudos
1
Bookmarks
As I said before, if we do not know that the sides are equal length AND the angles are all equal the answer should be E. Here is why:

We are still missing a piece of necessary information if we combine #1 and #2. I think we can all agree at this point that each independent statement is insufficient and the choices really come down to C or E.

If we want to use the information in #1 to multiply by 6 for the entire area of the hexagon, then we must be able to determine that all triangles created are equal, but in order to know that all triangles are equal, we must know that the sides of the hexagon are equal AND the angles are equal as well. Statement #2 only gives us the length of the sides as equal, and not the angles too. See the picture attached to my answer. The lines in the picture are all equal, but the triangles created in the interior are not equal, so by knowing the area of 1, we could not find the area of the others.

Answer E should be correct.
Attachment:
Hexagon.jpg
Hexagon.jpg [ 568.41 KiB | Viewed 12368 times ]


coelholds wrote:
In the figure above, three segments are drawn to connect opposite vertices of a hexagon, forming six triangles. All three of these segments intersect at point A. What is the area of the hexagon?

1) One of the triangles has an area of 12.
2) All the sides of the hexagon are of equal length.

Attachments

Hexagon.jpg
Hexagon.jpg [ 568.41 KiB | Viewed 12332 times ]

avatar
Manager
Manager
Joined: 21 Jun 2009
Posts: 94
Own Kudos [?]: 45 [0]
Given Kudos: 1
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
You certainly do have a point there.

What is the OA and explaination?
User avatar
Senior Manager
Senior Manager
Joined: 26 Apr 2009
Affiliations: ACA, CPA
Posts: 311
Own Kudos [?]: 272 [0]
Given Kudos: 41
Location: Vagabond
Concentration: Finance, Treasury, Banking
Schools:BC
GMAT 2: 620
WE 1: Big4, Audit
WE 2: Banking
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
Will go with E.. nothing is given about the 3 line segments intersecting each other.
User avatar
Manager
Manager
Joined: 30 May 2009
Posts: 89
Own Kudos [?]: 757 [0]
Given Kudos: 0
 Q50  V39
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
I would go with E too. What is the OA?
User avatar
Current Student
Joined: 20 Jul 2009
Affiliations: ?
Posts: 132
Own Kudos [?]: 73 [0]
Given Kudos: 6
Location: Africa/Europe
Concentration: Entrepreneurship, Finance, Strategy
Schools:Kellogg; Ross ($$); Tuck
 Q48  V38
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
What I wanted to point out is that If all side of an hexagone are equal, then all angle are also equal.
hence we can solve this question.

Like a triangle, If a triangle has all sides equals, then the angles are equals too.

am I wrong? if this assumption is wrong therefore answer is E

what is OA?

Originally posted by madeinafrica on 29 Jul 2009, 04:03.
Last edited by madeinafrica on 29 Jul 2009, 05:26, edited 1 time in total.
User avatar
Manager
Manager
Joined: 03 Jul 2009
Posts: 81
Own Kudos [?]: 430 [0]
Given Kudos: 13
Location: Brazil
 Q50  V35
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
Yes guys OA is E ;)

That is why I have posted this question here.

This took me a while to believe.

The fact is that you need to visualize that figure that jallenmorris have attached.

Congrats!!!!
User avatar
Current Student
Joined: 20 Jul 2009
Affiliations: ?
Posts: 132
Own Kudos [?]: 73 [0]
Given Kudos: 6
Location: Africa/Europe
Concentration: Entrepreneurship, Finance, Strategy
Schools:Kellogg; Ross ($$); Tuck
 Q48  V38
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
coelholds wrote:
Yes guys OA is E ;)



Thanks guy :)

Could some one telle me where i'm wrong?
on wiki i can find this:

"The internal angles of a regular hexagon (where all of the sides are the same) are all 120° and the hexagon has 720 degrees T."

So I still think that if all side of an hexagon are the same, then all angles are equal.
hence I do not understant why answer is not C.
User avatar
Manager
Manager
Joined: 03 Jul 2009
Posts: 81
Own Kudos [?]: 430 [2]
Given Kudos: 13
Location: Brazil
 Q50  V35
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
1
Kudos
1
Bookmarks
madeinafrica, no problem. You are just stuck in the same problem that I was.

Pay attention in what you wrote:

"The internal angles of a regular hexagon..." ops!!! Did the question say that it is a REGULAR hexagon?

No, and that is why we can not assume that it is. Even with a such beautiful and perfect image in the question. Remember, in DATA SUFFICIENCY questions, the image is not on scale.

So, what about an hexagon as jallenmorris has posted? Imagine the extremities even more close until forming almost a square. Calculate the area of the triangles, and you will see they are different. That is because it is not a REGULAR hexagon. So, you can have a hexagon with equal legs, but different angles. BUT, you can not have a hexagon with the equal angles and different legs! ;)

It is clear now? If not, ask again, then I will try a more detail explanation.... ;)


PS.: If you liked the post, consider a kudo. I need just one more to access the GMATClub tests!!! :) Thank you
VP
VP
Joined: 30 Apr 2008
Posts: 1230
Own Kudos [?]: 951 [3]
Given Kudos: 32
Location: Oklahoma City
Concentration: Life
Schools:Hard Knocks
 Q47  V42
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
2
Kudos
1
Bookmarks
Here is another example of a hexagon with equal sides but unequal angles.

Only with regard to a triangle can we assume equal angles with equal sides. No other polygon fits into this situation.
Attachments

Hexagon.png
Hexagon.png [ 9.17 KiB | Viewed 12068 times ]

User avatar
Manager
Manager
Joined: 14 Nov 2008
Posts: 108
Own Kudos [?]: 653 [0]
Given Kudos: 3
Concentration: Entrepreneurship
Schools:Stanford...Wait, I will come!!!
 Q51  V36
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
jallenmorris wrote:
Here is another example of a hexagon with equal sides but unequal angles.

Only with regard to a triangle can we assume equal angles with equal sides. No other polygon fits into this situation.

Thanks. Kudos to you.
User avatar
Intern
Intern
Joined: 02 Oct 2011
Posts: 10
Own Kudos [?]: [0]
Given Kudos: 1
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
Taking statement 2 into consideration,the hexagon is regular.If its regular with divided by 3 line segments intersecting with their ends separated equally will lead equal triangle areas.that way we can get 6*12 as the area.When have i gone wrong.Please help
User avatar
Intern
Intern
Joined: 02 Oct 2011
Posts: 10
Own Kudos [?]: [0]
Given Kudos: 1
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
Thanks a lot for the eplination.I was still not convinced(may be because i dont have the math to prove either way) so went and checked in some math forum.2 hexagons are congruent IFF both sides and all internal angles are equal (which means its possible to construct more than one hexagon with equal sides).This means that the area cannot be estimated from just knowing the side length and all of them are equal
GMAT Tutor
Joined: 27 Oct 2017
Posts: 1905
Own Kudos [?]: 5588 [4]
Given Kudos: 236
WE:General Management (Education)
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
2
Kudos
2
Bookmarks
Expert Reply

TAKEAWAY



Only triangle is the polygon where equal sides proves regular polygon.
"If all sides of a triangle are equal, triangle is equilateral with all angles equal. It is a regular polygon."

"For polygons (other than triangle), equality of sides doesn't make it a regular polygon."
For example in quadrilateral, all sides equal proves Quadrilateral to be rhombus, not square.
we need additional information to prove the same.
Intern
Intern
Joined: 07 Jul 2021
Posts: 39
Own Kudos [?]: 22 [0]
Given Kudos: 21
Concentration: Marketing, Strategy
GMAT 1: 640 Q44 V33
GMAT 2: 690 Q46 V38
GMAT 3: 720 Q49 V39
WE:Marketing (Manufacturing)
Send PM
Re: In the figure above, three segments are drawn to connect [#permalink]
coelholds wrote:

In the figure above, three segments are drawn to connect opposite vertices of a hexagon, forming six triangles. All three of these segments intersect at point A. What is the area of the hexagon?

1) One of the triangles has an area of 12.
2) All the sides of the hexagon are of equal length.


Statement 1) obviously not sufficient. We have no indication that all triangles are same i.e. no indication that it is a regular hexagon
Statement 2) All sides maybe equal, but this is not enough to constrain the hexagon to be a regular hexagon! The angles could still be different.
Combining neither gives any indication that all triangles have same area (12) nor any indication that all angles are same. So not sufficient.
Ans E
GMAT Club Bot
Re: In the figure above, three segments are drawn to connect [#permalink]
Moderator:
Math Expert
92977 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne