There were 2 apples and 5 bananas in a basket. After : Data Sufficiency (DS)

BDSunDevil

Manager

Joined: 13 May 2011

Posts: 144

Own Kudos [?]: 509 [0]

Given Kudos: 11

Concentration: Supply Chain, Logistics

WE 1: IT 1 Yr

WE 2: Supply Chain 5 Yrs

Send PM

Re: apple and banana---29 [#permalink]

26 May 2012, 06:09

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

nevermoreflow

Intern

Joined: 02 Dec 2012

Posts: 33

Own Kudos [?]: 4 [1]

Given Kudos: 0

Schools: Anderson FEMBA '17

GMAT Date: 01-01-2014

Send PM

Re: apple and banana---29 [#permalink]

10 Apr 2014, 17:03

1

Bookmarks

BDSunDevil wrote:

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

ind23

Intern

Joined: 10 Apr 2014

Posts: 23

Own Kudos [?]: 48 [4]

Given Kudos: 3

Send PM

Re: apple and banana---29 [#permalink]

10 Apr 2014, 23:24

2

Kudos

2

Bookmarks

nevermoreflow wrote:

BDSunDevil wrote:

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

Well the way I look at this question is that there are two unknowns.

Number of apples added = x
Number of bananas added = y

If we have two different equation, we can find unique values of x & y

One equation can be made using the information in question => (2+x)/(5+y) = 1/2

Argument 1 gives us another equation => x = 2/3y
If you put x = 2/3y in first equation you will get a unique solution.
So, it is sufficient.

Argument 2 also gives us on equation => x+y = 5
Again a unique solution is possible. It
So, it is sufficient.

Hence, the answer is D.

----------------
Kudos, if you like

sahil7389

Intern

Joined: 03 May 2014

Posts: 43

Own Kudos [?]: 101 [0]

Given Kudos: 43

Concentration: Operations, Marketing

Schools: ISB '17 (D) IIMC (A) IIMB (D)

GMAT 1: 680 Q48 V34

GMAT 2: 700 Q49 V35

GPA: 3.6

WE:Engineering (Energy and Utilities)

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

18 Jul 2015, 12:04

nevermoreflow wrote:

BDSunDevil wrote:

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

Whatever value you take, the ratio remains same and so our answer also. By taking 4/6 you are taking extra 2 multiplied in both numerator and denominator, so whatever you take 4/6 or 6/9 or 8/12 answer will always be same.

Kekki

Intern

Joined: 06 Aug 2015

Posts: 4

Own Kudos [?]: 14 [3]

Given Kudos: 10

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

15 Sep 2015, 04:06

2

Kudos

1

Bookmarks

nevermoreflow wrote:

BDSunDevil wrote:

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

If you add 4 apples and 6 bananas then you have 6 apples and 11 bananas which isn't a ratio of 1:2.
Only 2 apples + 3 banans lead to a total of 4 apples and 8 bananas -> Ratio of 1:2. No other multiple of 2:3 would lead to a total ration of 1:2.

Therefore (1) is sufficient as we get a clear # value for apples and bananas.

Akshobh

Intern

Joined: 10 May 2015

Status:Looking to apply

Affiliations: Channel NewsAsia, MediaCorp

Posts: 1

Own Kudos [?]: 5 [0]

Given Kudos: 10

Location: Singapore

Akshobh: Giridharadas

Concentration: General Management, Marketing

WE:Broadcasting (Journalism and Publishing)

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

01 Nov 2015, 05:35

Can someone please post the solution to statement 2?

I know it's sufficient, but I can't understand why?

L

Bunuel

Math Expert

Joined: 02 Sep 2009

Posts: 92945

Own Kudos [?]: 619184 [2]

Given Kudos: 81609

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

01 Nov 2015, 09:03

1

Kudos

1

Bookmarks

Expert Reply

Akshobh wrote:

Can someone please post the solution to statement 2?

I know it's sufficient, but I can't understand why?

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

From the stem: $\frac{2+a}{5+b}=\frac{1}{2}$]

(2) A total of 5 apples and bananas were added --> $a+b=5$.

Solve these two equations to get a=2 and b=3.

B

mbaapp1234

Manager

Joined: 23 Dec 2013

Posts: 86

Own Kudos [?]: 81 [1]

Given Kudos: 23

Location: United States (CA)

Schools: HBS '20 (D) Stanford '20 (D) Yale '21 (A$) Tuck '21 (A) Wharton '21 (A) Sloan '21 (A)

GMAT 1: 710 Q45 V41

GMAT 2: 760 Q49 V44

GPA: 3.76

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

22 Jul 2017, 18:24

1

Kudos

Jcpenny wrote:

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

(2+A) / (5+B) = 1/2

4+2A = 5+B
2A = 1+B

The goal is to find A.

Statement 1) A = 2/3*B

2A = 1+B
A = 2B/3

3A = 2B
4A = 2+2B
-A = -2
A = 2
B = 3

Sufficient.

Statement 2) A+B = 5

A+B = 5
2A = 1+B

A = 5-B

2(5-B) = 1+B
10-2B = 1+B
9 = 3B
3=B
2=5

Sufficient.

B

Srinivas0512

Intern

Joined: 29 Oct 2019

Posts: 4

Own Kudos [?]: 0 [0]

Given Kudos: 261

Location: India

GMAT 1: 720 Q50 V38

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

03 Feb 2020, 00:15

nevermoreflow wrote:

BDSunDevil wrote:

If A apples were added and B bananas were added:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:

I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

I too approached the problem in the same manner. But you must remember that the question explicitly states that the new ratio is 1/2.
The only set that maintains this ratio is 4/8. Other values like 6/11, 8/14 violate this condition.

B

jmwon

Intern

Joined: 26 May 2019

Posts: 30

Own Kudos [?]: 39 [0]

Given Kudos: 249

Send PM

There were 2 apples and 5 bananas in a basket. After [#permalink]

10 Aug 2020, 18:28

There are 2 apples (A) and 5 bananas (B) initially, and then let x apples, and y bananas be added to get to new ratio of apples (A) to bananas (B) of 1:2.

Statement (1):

$x = \frac{2}{3} y$
Sufficient, have the relation between x and y, so can plug into the ratio equation to solve for x and then y.
To illustrate this:
Apples : Bananas
$\frac{(2 + x)}{(5 + y)} = \frac{1}{2}$
$(2 + \frac{2y}{3})/(5 + y) = \frac{1}{2}$
$2(2+ \frac{2}{3} y) = 5 + y$
$4 + \frac{4}{3} y = 5 + y$
$y = 3$
$x = 2/3 y$
$x = 2$

Statement (2):

$x + y = 5$
Also sufficient since have the total of x and y.
Still can solve for x to illustrate:
$y = 5 - x$
$\frac{(2 + x)}{(5 + 5 - x)} = \frac{1}{2}$
$\frac{(2 + x)}{(10 - x)} = \frac{1}{2}$
$2(2 + x) = 10 - x$
$x = 2$

Jcpenny wrote:

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

B

adkor95

Intern

Joined: 06 Mar 2020

Posts: 34

Own Kudos [?]: 13 [0]

Given Kudos: 80

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

11 Sep 2020, 05:31

icandy wrote:

Jcpenny wrote:

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2 . How many apples were added?
(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Given

A=2, B =5

2+X/ 5+Y = 1/2

(1) says X=2/3Y

2 eq's 2 unknowns. Solve for x to get the answer. Suff

(2) says X +Y =5

2 eq's 2 unknowns. Solve for x to get the answer. Suff

D

Thanks! But can you expand on '2 eq's 2 unknowns.' a little bit please? I know how to substitute/eliminate linear equations, but understanding the rule could help me with speed.

G

Basshead

Director

Joined: 09 Jan 2020

Posts: 966

Own Kudos [?]: 223 [1]

Given Kudos: 434

Location: United States

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

15 Dec 2020, 20:21

1

Kudos

Jcpenny wrote:

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

$\frac{2 + A }{ 5 + B} = \frac{1}{2}$

What is A?

(1) $\frac{A }{ B} = \frac{2 }{ 3}$
$2B = 3A$
$\frac{2B}{3} = A$

2 + 2B/3 / 5 + B = 1/2

B = 3, A = 2

SUFFICIENT

(2) Directly gives us our answer; SUFFICIENT.

Answer is D.

D

avigutman

Tutor

Joined: 17 Jul 2019

Posts: 1304

Own Kudos [?]: 2287 [1]

Given Kudos: 66

Location: Canada

Schools: NYU Stern (WA)

GMAT 1: 780 Q51 V45 Verified score

GMAT 2: 780 Q50 V47 Verified score

GMAT 3: 770 Q50 V45 Verified score

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

14 Mar 2022, 05:09

1

Kudos

Expert Reply

Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1

G

TargetMBA007

Manager

Joined: 22 Nov 2019

Posts: 232

Own Kudos [?]: 100 [1]

Given Kudos: 197

Schools: Stanford MSx '25 HBS '26

GPA: 4

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

03 Dec 2023, 06:29

1

Kudos

Correct TAG:Gmatprep

Bunuel

L

Bunuel

Math Expert

Joined: 02 Sep 2009

Posts: 92945

Own Kudos [?]: 619184 [0]

Given Kudos: 81609

Send PM

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

03 Dec 2023, 06:52

Expert Reply

TargetMBA007 wrote:

Correct TAG:Gmatprep

Bunuel

_________________________
Added the tag. Thank you!

gmatclubot

Re: There were 2 apples and 5 bananas in a basket. After [#permalink]

03 Dec 2023, 06:52

GMAT Data Sufficiency (DS) Questions

There were 2 apples and 5 bananas in a basket. After