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# There were 2 apples and 5 bananas in a basket. After

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Manager
Joined: 10 Oct 2008
Posts: 56
There were 2 apples and 5 bananas in a basket. After  [#permalink]

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08 Nov 2008, 18:15
4
17
00:00

Difficulty:

35% (medium)

Question Stats:

68% (00:51) correct 32% (00:49) wrong based on 627 sessions

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There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.
VP
Joined: 05 Jul 2008
Posts: 1329

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08 Nov 2008, 18:49
6
7
Jcpenny wrote:
There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2 . How many apples were added?
(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

Given

A=2, B =5

2+X/ 5+Y = 1/2

(1) says X=2/3Y

2 eq's 2 unknowns. Solve for x to get the answer. Suff

(2) says X +Y =5

2 eq's 2 unknowns. Solve for x to get the answer. Suff

D
##### General Discussion
Manager
Joined: 07 Sep 2011
Posts: 61
Location: United States
GMAT 1: 640 Q39 V38
WE: General Management (Real Estate)

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26 May 2012, 05:06
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Jcpenny wrote:
There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2 . How many apples were added?
(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Senior Manager
Joined: 13 May 2011
Posts: 255
WE 1: IT 1 Yr
WE 2: Supply Chain 5 Yrs

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26 May 2012, 06:09
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?
Intern
Joined: 02 Dec 2012
Posts: 33
GMAT Date: 01-01-2014

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10 Apr 2014, 17:03
BDSunDevil wrote:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).
Intern
Joined: 10 Apr 2014
Posts: 33

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10 Apr 2014, 23:24
1
nevermoreflow wrote:
BDSunDevil wrote:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

Well the way I look at this question is that there are two unknowns.

Number of apples added = x
Number of bananas added = y

If we have two different equation, we can find unique values of x & y

One equation can be made using the information in question => (2+x)/(5+y) = 1/2

Argument 1 gives us another equation => x = 2/3y
If you put x = 2/3y in first equation you will get a unique solution.
So, it is sufficient.

Argument 2 also gives us on equation => x+y = 5
Again a unique solution is possible. It
So, it is sufficient.

----------------
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GMAT 1: 680 Q48 V34
GMAT 2: 700 Q49 V35
GPA: 3.6
WE: Engineering (Energy and Utilities)
Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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18 Jul 2015, 12:04
nevermoreflow wrote:
BDSunDevil wrote:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

Whatever value you take, the ratio remains same and so our answer also. By taking 4/6 you are taking extra 2 multiplied in both numerator and denominator, so whatever you take 4/6 or 6/9 or 8/12 answer will always be same.
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Intern
Joined: 06 Aug 2015
Posts: 5
Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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15 Sep 2015, 04:06
nevermoreflow wrote:
BDSunDevil wrote:
(2+A)/(5+B)=1/2
Statement 1: is telling 2 bananas were added for every 3 apple added. i. e. A=2/3 B . plugging the value of B we can solve for A.
Statement 2: A+B=5. similar as statement 1. can solve for A.

D.

manjeet1972 wrote:
I thought the answer should be C.

In case of statement 1, we can have multiple values of banana and apple. There can be 5 apples and 10 banana thus adding 3 apples and 5 bananas and there can also be 10 apples and 20 bananas giving ratio of 1/2 but apples added will be 8 and 15 banana.

Can someone clarify if I am missing something?

Isn't (1) saying the # of apples to bananas is 2:3? So for every 2 apples, there are 3 bananas? Couldn't it be 4 to 6, 6 to 9, etc? We can't get an exact amount of apples that were added from this like this question is asking for.

(2) is clearly sufficient, but I'm having issues with (1).

If you add 4 apples and 6 bananas then you have 6 apples and 11 bananas which isn't a ratio of 1:2.
Only 2 apples + 3 banans lead to a total of 4 apples and 8 bananas -> Ratio of 1:2. No other multiple of 2:3 would lead to a total ration of 1:2.

Therefore (1) is sufficient as we get a clear # value for apples and bananas.
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Joined: 10 May 2015
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Location: Singapore
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Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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01 Nov 2015, 05:35
Can someone please post the solution to statement 2?

I know it's sufficient, but I can't understand why?
Math Expert
Joined: 02 Sep 2009
Posts: 47981
Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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01 Nov 2015, 09:03
1
Akshobh wrote:
Can someone please post the solution to statement 2?

I know it's sufficient, but I can't understand why?

There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

From the stem: $$\frac{2+a}{5+b}=\frac{1}{2}$$]

(2) A total of 5 apples and bananas were added --> $$a+b=5$$.

Solve these two equations to get a=2 and b=3.
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GMAT 1: 710 Q45 V41
GMAT 2: 760 Q49 V44
GPA: 3.76
Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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22 Jul 2017, 18:24
1
Jcpenny wrote:
There were 2 apples and 5 bananas in a basket. After additional apples and bananas were placed in the basket, the ratio of the number of apples to the number of bananas was 1/2. How many apples were added?

(1) The number of apples added was 2/3 the number of bananas added.
(2) A total of 5 apples and bananas were added.

(2+A) / (5+B) = 1/2

4+2A = 5+B
2A = 1+B

The goal is to find A.

Statement 1) A = 2/3*B

2A = 1+B
A = 2B/3

3A = 2B
4A = 2+2B
-A = -2
A = 2
B = 3

Sufficient.

Statement 2) A+B = 5

A+B = 5
2A = 1+B

A = 5-B

2(5-B) = 1+B
10-2B = 1+B
9 = 3B
3=B
2=5

Sufficient.
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Re: There were 2 apples and 5 bananas in a basket. After  [#permalink]

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02 Aug 2018, 04:53
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