In a sprint race, a man has to run two distances, D1 and D2, to comple

OFFICIAL EXPLANATION FROM Egmat

Correct Answer: A

Steps 1 & 2: Understand Question and Draw Inferences

Given:
* A man a man has to run two distances, D1 and D2, to complete a sprint race.
* Jim is participating in the race.
* Distance D2 is thrice of the distance D1.

To Find:
* Average speed of Jim. Average Speed = Total distance covered/Total time taken
* Total distance covered = D1 + D2 = D1 + 3 D1= 4D1
* Total time taken= Time taken to cover D1 + Time taken to cover D2
Time taken to cover \(D_1 = \frac{D_1}{S_1}\) , where S1 is the speed to cover D1.
Time taken to cover \(D_2 = \frac{D_2}{S_2} = \frac{(3D_1)}{S_2}\) , where S2 is the speed to cover D2.
* Average Speed = \(\frac{(4D_1)}{(Time \ taken \ to \ cover \ D_1+ Time \ taken \ to \ cover \ D_2 )} = \frac{4D_1}{\frac{D_1}{S_1} + \frac{D_2}{S_2}} = \frac{4D_1}{\frac{D_1}{S_1} + \frac{3D_1}{S_2}}= \frac{4}{\frac{1}{S_1} + 3S_2}\)
* We need S1 and S2 to find the answer.

We do not have enough information to find the answer, let us analyze the statements.

Step 3: Analyse Statement 1:
“Jim covered the distance D1 by running at 1 kilometer per hour and distance D2 by running at 6 kilometers per hour.”
* S1 = 1 and S2 = 6
Therefore, statement 1 alone is sufficient.

Step 4: Analyse Statement 2:
“The amount of time Jim took to cover distance D1 was twice of the time it took him to cover distance D2.”
* Time taken to cover D1 = 2 × Time taken to cover D2
* \(\frac{D_1}{S_1} = 2 × \frac{(3D_1)}{S_2}\)
* \(\frac{1}{S_1} =\frac{6}{S_2}\)
* \(S_2 = 6S_1\)
This statement gives a relation between S1 and S2. However, we can find the value of S1 and S2.
Therefore, statement 2 alone is NOT sufficient.

Step 5: Analyse both statements together:
This step is not required, since, we got the answer from statement 1

Hence, the correct answer is Option A.