1/(1+1/3)-1/(1+1/2) : GMAT Problem Solving (PS)
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# 1/(1+1/3)-1/(1+1/2)

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Math Expert
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26 Aug 2012, 01:59
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Difficulty:

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Question Stats:

89% (01:32) correct 11% (00:41) wrong based on 1030 sessions

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$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

Practice Questions
Question: 27
Page: 155
Difficulty: 550
[Reveal] Spoiler: OA

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26 Aug 2012, 01:59
SOLUTION:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}$$.

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26 Aug 2012, 07:22
By taking the LCM and taking the reciprocals-

3/4-2/3=1/12
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27 Aug 2012, 10:07
Ans = (3/4) - (2/3) = 1/12
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28 Aug 2012, 03:10

3/4 - 2/3 = 1/12
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28 Aug 2012, 07:28
bunuel.. i think difficulty level shud be 500 or below 500..

its 1/12.. person shud knw the 1+1/3 = 4/3.. by not taking LCM because that will waste ur time..
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31 Aug 2012, 00:53
SOLUTION:

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$$

(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3

$$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}=\frac{3}{4}-\frac{2}{3}=\frac{1}{12}$$.

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22 Apr 2014, 02:27
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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10 May 2016, 17:18
Attached is a visual that should help.
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Screen Shot 2016-05-10 at 5.50.27 PM.png [ 75.73 KiB | Viewed 2885 times ]

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11 May 2016, 01:59
1/(4/3)-1/(3/2)= 3/4- 2/3= 9-8/12=1/12
Re: 1/(1+1/3)-1/(1+1/2)   [#permalink] 11 May 2016, 01:59
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# 1/(1+1/3)-1/(1+1/2)

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