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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
(30/sqrt 2)^2 = 450
Correct answer - B
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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
Bunuel wrote:
AbdurRakib wrote:
If a square mirror has a 30-inch diagonal, what is the area of the mirror, in inches?

A. 225

B. 450

C. 600

D. 750

E. 900


Merging topics. Please search before posting.


Thanks But,
Actuality I searched on the Google but found only this link if-a-square-mirror-has-a-20-inch-diagonal-what-is-the-99359.html

I'll search it next time on GMATCLUB to avoid mistake

Thanks again
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If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
Bunuel wrote:
If a square mirror has a 30-inch diagonal, what is the area of the mirror, in inches?

A. 225
B. 450
C. 600
D. 750
E. 900


Kudos for correct solution.


If a square has a side a, then the length of the diagonal is \(a* \sqrt{2}\)

Area of square would be \(a^2\)

\(a\sqrt{2}\) = 30;

squaring both sides
2\(a^2\) = 30*30 = 900
\(a^2\) = 450 --> This is the area.

Answer: B.
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If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
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Bunuel wrote:
If a square mirror has a 30-inch diagonal, what is the area of the mirror, in inches?

A. 225
B. 450
C. 600
D. 750
E. 900

Kudos for correct solution.

Given a square's diagonal, we need side lengths to calculate area.

The relationship between a square's side, s, and its diagonal, d,* is given by

\(s\sqrt{2} = d\)
\(s = \frac{d}{\sqrt{2}}\)

The side of square (d = 30), therefore, is \(\frac{30}{\sqrt{2}}\).

Leave it; no need to rationalize the denominator because it needs to be squared. Square the side length to find area:

\((\frac{30}{\sqrt{2}}\) * \(\frac{30}{\sqrt{2}})\) = \(\frac{30*30}{2}\) = \(\frac{900}{2}=450\)

Answer B

*Although \(d = s\sqrt{2}\) probably should be in memory, it is easily derived. Two sides, \(s\), of a square, form a right isosceles triangle. Pythagorean theorem hence yields:
\(s^2 + s^2 = d^2\)
\(2s^2 = d^2\)
\((\sqrt{2})(\sqrt{s^2})=\sqrt{d^2}\)
\((\sqrt{2})s\\
= d\), or \(s\sqrt{2}= d\)
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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
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Expert Reply
Bunuel wrote:
If a square mirror has a 30-inch diagonal, what is the area of the mirror, in inches?

A. 225
B. 450
C. 600
D. 750
E. 900


Since the diagonal of a square is 30:

diagonal = side√2

30 = side√2

Squaring the entire equation, we have:

30^2 = side^2 x 2

900/2 = side^2

450 = side^2 = area

Answer: B
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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
Area = (diag 1)* (diag 2)/2

so, Area of the mirror = 30*30/2= 450 sq inch
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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
s²+s² = 30²

2s² = 900

s² = 450 = the answer
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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
It's easier if you use the formula for the area of the rhombus (d1*d2/2). A square is a rhombus with diagonals of the same length, then:
A = (30in)(30in)/2 = 450 in²

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Re: If a square mirror has a 30-inch diagonal, what is the area of the mir [#permalink]
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