Last visit was: 25 Apr 2024, 20:15 It is currently 25 Apr 2024, 20:15

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
Retired Moderator
Joined: 27 Aug 2012
Posts: 1015
Own Kudos [?]: 4054 [31]
Given Kudos: 156
Send PM
Most Helpful Reply
GMAT Club Legend
GMAT Club Legend
Joined: 12 Sep 2015
Posts: 6820
Own Kudos [?]: 29933 [10]
Given Kudos: 799
Location: Canada
Send PM
Verbal Forum Moderator
Joined: 10 Oct 2012
Posts: 485
Own Kudos [?]: 3093 [7]
Given Kudos: 141
Send PM
General Discussion
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619042 [1]
Given Kudos: 81595
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
1
Kudos
Expert Reply
bagdbmba wrote:
A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 3 letters in its codes, and all letters can be repeated in any one code?

A.15600
B.16226
C.17576
D.18278
E.28572


Similar question from GMAT Prep:
Quote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?

A. 2,951
B. 8,125
C. 15,600
D. 16,302
E. 18,278


Discussed here: a-certain-stock-exchange-designates-each-stock-with-a-86656.html

Other similar questions to practice:
all-of-the-stocks-on-the-over-the-counter-market-are-126630.html
if-a-code-word-is-defined-to-be-a-sequence-of-different-126652.html
the-simplastic-language-has-only-2-unique-values-and-105845.html
a-4-letter-code-word-consists-of-letters-a-b-and-c-if-the-59065.html
a-certain-stock-exchange-designates-each-stock-with-a-86656.html
a-5-digit-code-consists-of-one-number-digit-chosen-from-132263.html
a-company-that-ships-boxes-to-a-total-of-12-distribution-95946.html
a-company-plans-to-assign-identification-numbers-to-its-empl-69248.html
the-security-gate-at-a-storage-facility-requires-a-five-109932.html
all-of-the-bonds-on-a-certain-exchange-are-designated-by-a-150820.html
a-local-bank-that-has-15-branches-uses-a-two-digit-code-to-98109.html
a-researcher-plans-to-identify-each-participant-in-a-certain-134584.html
baker-s-dozen-128782-20.html#p1057502
in-a-certain-appliance-store-each-model-of-television-is-136646.html
m04q29-color-coding-70074.html
john-has-12-clients-and-he-wants-to-use-color-coding-to-iden-107307.html
how-many-4-digit-even-numbers-do-not-use-any-digit-more-than-101874.html
a-certain-stock-exchange-designates-each-stock-with-a-85831.html

Hope it helps.
Retired Moderator
Joined: 27 Aug 2012
Posts: 1015
Own Kudos [?]: 4054 [1]
Given Kudos: 156
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
1
Kudos
Thanks Bunuel for not only referring to the solution but also sharing several similar problems for practice.
Really appreciate it.

+1 Sir!
Target Test Prep Representative
Joined: 04 Mar 2011
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Posts: 3043
Own Kudos [?]: 6275 [0]
Given Kudos: 1646
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
Expert Reply
bagdbmba wrote:
A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 3 letters in its codes, and all letters can be repeated in any one code?

A.15600
B.16226
C.17576
D.18278
E.28572


A one-letter code can be formed in 26 ways.

A two-letter code can be formed in 26 x 26 = 26^2 ways.

A three-letter code can be formed in 26 x 26 x 26 = 26^3 ways.

Thus, the total number of codes is:

26 + 26^2 + 26^3

26(1 + 26 + 26^2)

26(1 + 26 + 676)

26(703) = 18,278

Notice that one need not do the multiplication out fully. We see that the units digit is an 8.

Answer: D
Director
Director
Joined: 13 Mar 2017
Affiliations: IIT Dhanbad
Posts: 628
Own Kudos [?]: 589 [1]
Given Kudos: 88
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE:Engineering (Energy and Utilities)
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
1
Bookmarks
bagdbmba wrote:
A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 3 letters in its codes, and all letters can be repeated in any one code?

A.15600
B.16226
C.17576
D.18278
E.28572


So product codes can be o f 1 letter or 2 letter or 3 letters and all the letters can be repeated in any code.
So product codes possible = 26 + 26*26 + 26*26*26 = 26(1+26+26^2) = 26*(27+676) = 26* (703) = 18278

Answer D
Manager
Manager
Joined: 10 Jan 2023
Posts: 81
Own Kudos [?]: 30 [0]
Given Kudos: 33
Location: India
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
JeffTargetTestPrep wrote:
bagdbmba wrote:
A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 3 letters in its codes, and all letters can be repeated in any one code?

A.15600
B.16226
C.17576
D.18278
E.28572


A one-letter code can be formed in 26 ways.

A two-letter code can be formed in 26 x 26 = 26^2 ways.

A three-letter code can be formed in 26 x 26 x 26 = 26^3 ways.

Thus, the total number of codes is:

26 + 26^2 + 26^3

26(1 + 26 + 26^2)

26(1 + 26 + 676)

26(703) = 18,278

Notice that one need not do the multiplication out fully. We see that the units digit is an 8.

Answer: D


In 2 letter code and 3 letter code , the 2 codes or 3 codes can be similar for eg. AA or AAA , then why are we not dividing in case of AA or AAA by 2! & 3! respectively ?
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619042 [1]
Given Kudos: 81595
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
1
Kudos
Expert Reply
Gangadhar111990 wrote:
JeffTargetTestPrep wrote:
bagdbmba wrote:
A company assigns product codes consisting of all the letters in the alphabet.How many product codes are possible if the company uses at most 3 letters in its codes, and all letters can be repeated in any one code?

A.15600
B.16226
C.17576
D.18278
E.28572


A one-letter code can be formed in 26 ways.

A two-letter code can be formed in 26 x 26 = 26^2 ways.

A three-letter code can be formed in 26 x 26 x 26 = 26^3 ways.

Thus, the total number of codes is:

26 + 26^2 + 26^3

26(1 + 26 + 26^2)

26(1 + 26 + 676)

26(703) = 18,278

Notice that one need not do the multiplication out fully. We see that the units digit is an 8.

Answer: D


In 2 letter code and 3 letter code , the 2 codes or 3 codes can be similar for eg. AA or AAA , then why are we not dividing in case of AA or AAA by 2! & 3! respectively ?


With the method provided, you get one codes 'AA' and and one code 'AAA'. Why consider a factorial correction? Factorial division is used to eliminate duplicates. What would you exclude here? Dividing these by a factorial isn't necessary, as they are unique combinations, not duplicates.
Manager
Manager
Joined: 10 Jan 2023
Posts: 81
Own Kudos [?]: 30 [0]
Given Kudos: 33
Location: India
Send PM
A company assigns product codes consisting of all the letter [#permalink]
In 2 letter code and 3 letter code , the 2 codes or 3 codes can be similar for eg. AA or AAA , then why are we not dividing in case of AA or AAA by 2! & 3! respectively ?[/quote]

With the method provided, you get one codes 'AA' and and one code 'AAA'. Why consider a factorial correction? Factorial division is used to eliminate duplicates. What would you exclude here? Dividing these by a factorial isn't necessary, as they are unique combinations, not duplicates.[/quote]

Ok, so if the question stem mentions that "AA" is identical then would we be diving by 2! , Correct ?
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619042 [0]
Given Kudos: 81595
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
Expert Reply
Gangadhar111990 wrote:
Ok, so if the question stem mentions that "AA" is identical then would we be diving by 2! , Correct ?
Bunuel


Not sure I follow. What do you mean by "if the question stem mentions that "AA" is identical "?
Manager
Manager
Joined: 10 Jan 2023
Posts: 81
Own Kudos [?]: 30 [0]
Given Kudos: 33
Location: India
Send PM
Re: A company assigns product codes consisting of all the letter [#permalink]
Bunuel wrote:
Gangadhar111990 wrote:
Ok, so if the question stem mentions that "AA" is identical then would we be diving by 2! , Correct ?
Bunuel


Not sure I follow. What do you mean by "if the question stem mentions that "AA" is identical "?



So if the Question stem is mentioning that "same letters for codes are identical " then what changes would we be making in the solution ?
GMAT Club Bot
Re: A company assigns product codes consisting of all the letter [#permalink]
Moderators:
Math Expert
92915 posts
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne