Bunuel wrote:

rakeshd347 wrote:

All of the bonds on a certain exchange are designated by a 3-letter, a 4-letter, or a 5-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different bonds that can be designate with these codes?

(A) 26(26^3 + 26^4)

(B) 26(26^3 + 26^5)

(C) 27(26^3 + 26^5)

(D) 27(26^3) + 26^5

(E) 26^3 + 27(26^5)

FCP - Answers above use the

Fundamental Counting Principle to find

total possible code combinations for each kind/category

of code (3-, 4-, and 5-letter codes)

•

FCP: If a task can be broken into stages &

Stage 1 can be done in

X ways;

Stage 2 can be done in

Y ways; and

Stage 3 can be done in

Z ways,

Then the

total number of ways to do the task

= X * Y * Z • The "tasks" are to create 3-, 4-, and 5-letter codes.

Each is a separate task.

Each can be broken into stages.

3-letter code's possibilities?Stages are like "slots" into which letters are placed

• Stages/

slots in 3-letter code:

___ ___ ___First slot: there are

26 letters from which to

choose, hence 26 possibilitiesSecond slot: also 26 possibilities ("FCP without restriction")*

If using the same letter is not allowed, the prompt will say so

Third slot: also 26 possibilities

• 3-letter codes possible:

26*26*26=

\(26^3\)Possibilities for each type of code•

3-letter code has

\(26^3\) possibilities

•

4-letter code's possibilities?

_26_*

_26_*

_26_*

_26_ =

\(26^4\)•

5-letter code's possibilities?

\(26^5\)Now ADD each set's # of possibilities

Sets are 3-, 4-, and 5-letter codes.

One bond gets only one code.

But the

total pool of codes for each bond

consists of possibilities from the 3-, 4-, and 5-letter sets

•

ADD sets' possibilities: \(26^3 + 26^4 + 26^5\) = ?Rearrange answer to match answer choices

\(26^3 + 26^4 + 26^5\)Often, we would factor out

\(26^3\):

\(26^3(26^1 + 26^2)\)Not an option. But in the options...

\(26^4\) appears only one time, whereas

\(26^3\) and

\(26^5\) appear FOUR times

Get rid of \(26^4\)\(26^3 + 26^4 + 26^5 =\)

\((26^3 + 26^4) + 26^5 =\)

\(26^3(1 + 26^1) + 26^5 =\)

\(26^3(27) + 26^5 =\)

\((27)26^3 + 26^5 =\)Answer D*"FCP without restriction"? For each code, choosing the first letter does not affect the second choice.

If I choose M for slot 1, I can choose M for slot 2, and M for slot 3. That is, after the choice for slot 1, there are

no restrictions on subsequent choices/slots. "FCP w/o restriction."

IF, however, the prompt said, "no repeat letters," we would have "FCP with restriction":

First choice: 26 letters. Can't repeat letters. The choice for slot 1 removed one (restricted the) choice for slot 2.

Second choice: only 25 possibilities. Third choice: 24 possibilities.

Choices for subsequent slots ARE restricted. 3-letter code using FCP with restriction: (26*25*24)
_________________

In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"