Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

100 people are attending a newspaper conference. 45 of them [#permalink]
16 Feb 2012, 20:34

5

This post received KUDOS

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (medium)

Question Stats:

45% (02:41) correct
55% (01:33) wrong based on 437 sessions

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?

Re: Writers and editors. [#permalink]
16 Feb 2012, 20:51

7

This post received KUDOS

Expert's post

calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? 6 16 17 33 84

100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=55-39=16.

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]
05 Mar 2012, 12:25

5

This post received KUDOS

question stem total=100 W=45 E= more than 38 W-and-E=x Neither=2x x? answer- 100=45+39+2x-x (to maximize x we need to minimize E. that is why E=39 the least value) x=16 _________________

Happy are those who dream dreams and are ready to pay the price to make them come true

Helpful Geometry formula sheet:best-geometry-93676.html I hope these will help to understand the basic concepts & strategies. Please Click ON KUDOS Button.

Re: 100 people are attending a newspaper conference. 45 of them [#permalink]
11 Apr 2014, 01:32

calreg11 wrote:

100 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?

A. 6 B. 16 C. 17 D. 33 E. 84

W + E - Both + Neither = 100

45 + E - (x) + 2x = 100

45 + E + x = 100

Now let us plug in answer options:

We cannot plug in 84 as E will become negative If we plug in x = 33 then E = 22 (Wrong as there are more than 38 editors) If we plug in x = 17 then E = 38 (Wrong as there are more than 38 editors) Hence answer is x= 16 _________________

Perfect Scores

If you think our post was valuable then please encourage us with Kudos