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Re: If j and k are positive integers and j + k is odd [#permalink]
guerrero25 wrote:
If j and k are positive integers and j + k is odd, what is the value of k?

(1) When j is divided by k, the remainder is 3

(2) \(j > 7 > 6 > k\)


Official solution from Veritas Prep.

E. Statement 1 is not sufficient, as there are infinite combinations of values. For example, if j is 3, then k could be any even number > 4. Statement 2 is also not sufficient, as k could be any integer 1 through 5. Taken together, the statements are still not sufficient, as j and k could be 11 and 4 (leaving 2 remainder 3) or 8 and 5 (1 remainder 3). The "trap" here is that 8 and 5 are the only values that work for the quotient to be 1 with the remainder 3. But because j could be any large number, the possibilities are endless.
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Re: If j and k are positive integers and j + k is odd [#permalink]
guerrero25 wrote:
If j and k are positive integers and j + k is odd, what is the value of k?

(1) When j is divided by k, the remainder is 3

(2) j > 7 > 6 > k


given condition that j and k are positive integers and j + k is odd
j+k odd means either of them is even and odd
so k can be even or odd
#1
When j is divided by k, the remainder is 3
j,k possible pairs ; ( 3,6) ; (3,10) ; ( 9,6) insufficient
#2
j > 7 > 6 > k
many possible pairs of j,k where odd+even are values
insufficient
from 1 &2
we can have j,k pairs ; ( 8,5) ; ( 7,4)
insufficient
OPTION E
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Re: If j and k are positive integers and j + k is odd [#permalink]
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Re: If j and k are positive integers and j + k is odd [#permalink]
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