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If xy≠0 and x^2*y^2-xy=6, which of the following could be y

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If xy≠0 and x^2*y^2-xy=6, which of the following could be y [#permalink] New post 16 Jan 2012, 10:26
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Question Stats:

81% (02:30) correct 19% (01:46) wrong based on 52 sessions
If xy not equal 0 and x^2*y^2 -xy = 6, which of the following could be y in terms of x?

I. 1/2x
II. -2/x
III. 3/x

A. I only
B. II only
C. I and II
D. I and III
E. II and III
[Reveal] Spoiler: OA

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Re: if xy not equal 0 and x^2*y^2 -xy = 6 [#permalink] New post 16 Jan 2012, 11:46
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If xy≠0 and x^2*y^2-xy=6, which of the following could be y in terms of x?

I. 1/(2x)
II. - 2/x
III. 3/x

x^2*y^2-xy=6 --> (xy)^2-xy-6=0 --> factor quadratics for xy: (xy-3)(xy+2)=0 (or just solve quadratics for xy) --> either xy-3=0 and in this case y=3/x or xy+2=0 and in this case y=-2/x.

Answer: E.

Factoring Quadratics: http://www.purplemath.com/modules/factquad.htm

Solving Quadratic Equations: http://www.purplemath.com/modules/solvquad.htm

Hope it helps.
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Re: If xy≠0 and x^2*y^2-xy=6, which of the following could be y [#permalink] New post 17 Jan 2012, 02:51
Ans is E. Simply put xy = a and solve the equation to get 2 values of xy
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Re: If xy≠0 and x^2*y^2-xy=6, which of the following could be y [#permalink] New post 02 Sep 2013, 08:57
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Re: If xy≠0 and x^2*y^2-xy=6, which of the following could be y   [#permalink] 02 Sep 2013, 08:57
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If xy≠0 and x^2*y^2-xy=6, which of the following could be y

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