manalq8 wrote:
Hi everyone,
I can't figure out what wrong did I do. here is the problem:
A bottle is 80% full. the liquid in the bottle consists of 60% guava juice and 40% pineapple juice. the remainder of the bottle is then filled with 70 lm of rum. How much guava is in the bottle?
here is how I approached it:
since 80% filled, then 20%of x= 70lm
so x, the capacity, = 70/ .2= 350 lm, the total capacity of the bottle
since 60% of the liquid is guava juice, then .6(350)=210 lm
hence, 210 is the guava juice in the bottle and this is the answer that i got.
but the answer in the book is 168 lm, so can someone please tell me what's the problem with my approach?
please, help
thank you so much
The question tells you the following:
A bottle is 80% full of a liquid. [highlight]60% of the liquid[/highlight] is guava juice and [highlight]40% of the liquid[/highlight] is pineapple juice. (mind you, this is not 60% of the bottle. Say, if the bottle's volume is 100 ml, liquid in it is 80 ml. Guava juice is 60% of the 80 ml (= 48 ml), not of the 100 ml. Similarly, pineapple juice is 40% of the 80 ml (= 32 ml) )
So what [highlight]% of the bottle[/highlight] is full of guava juice? 60% of the 80% = 48%
What [highlight]% of the bottle[/highlight] is full of pineapple juice? 40% of the 80% = 32%
Total 48%+32% = 80% as expected since the total liquid in the bottle is 80%
Rum = 20% of the bottle which is 70 ml
Total volume of the bottle = 350 ml
Guava juice is 48% of the bottle = 48% of 350 = 168 ml