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14 Jan 2021, 11:51
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well, it's pretty straight forward.
20% of the content in that bottle represents 70 ml (of rum), so the rest 80% would be= (70)4= 280ml (80% content of the bottle) keep in mind this includes that 20% rum and everything else.
now, for guava, simply calculate 60% of the total content, which is, 280ml=(6/10)*280= 168ml. Voila !
20% of the content in that bottle represents 70 ml (of rum), so the rest 80% would be= (70)4= 280ml (80% content of the bottle) keep in mind this includes that 20% rum and everything else.
now, for guava, simply calculate 60% of the total content, which is, 280ml=(6/10)*280= 168ml. Voila !
02 Feb 2021, 09:19
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VeritasKarishma
Sharing the step-by-step approach using algebra
1. Let the volume of the bottle be \(x\)
2. We are told that the actual contents in the bottle constitute \(80%\) of the bottle i.e. \(\frac{4x}{5}\)
3. Guava constitutes \(60%\) of the contents or \(\frac{4x}{5} * \frac{3}{5} = \frac{12x}{25}\)
4. Pineapple constitutes \(40%\) of the contents or \(\frac{4x}{5} * \frac{2}{5} = \frac{8x}{25}\)
5. The remaining \(20%\) of the bottle is filled with Rum i.e. \(1 - \frac{4x}{5} = 70\) -> \(\frac{x}{5} = 70\) -> \(x = 350\)
6. We are asked to find the volume of Guava, which would be \(\frac{12x}{25} = \frac{12 * 350}{25} = 168\) ml
Ans. A
02 Feb 2021, 09:20
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VeritasKarishma
Sharing the step-by-step approach using algebra
1. Let the volume of the bottle be \(x\)
2. We are told that the actual contents in the bottle constitute 80% of the bottle i.e. \(\frac{4x}{5}\)
3. Guava constitutes 60% of the contents or \(\frac{4x}{5} * \frac{3}{5} = \frac{12x}{25}\)
4. Pineapple constitutes 40% of the contents or \(\frac{4x}{5} * \frac{2}{5} = \frac{8x}{25}\)
5. The remaining 20% of the bottle is filled with Rum i.e. \(1 - \frac{4x}{5} = 70\) -> \(\frac{x}{5} = 70\) -> \(x = 350\)
6. We are asked to find the volume of Guava, which would be \(\frac{12x}{25} = \frac{12 * 350}{25} = 168\) ml
Ans. A
