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2. According to the graph below, when x = 3, y most nearly ? (A) –1 (B) (C) 0 (D) (E) 1

With the given options, E? From the graph, y=3,x=0, y=0,x=2, so if it is symmetric, y=3,x=4. And for x=3,y=1.5 (rounded off to 2, but 2 is not one of the options). is it a official prep Q?

Sorry mate; completely forgot that it is a parabolic equation.. In my opinion it will take at least 90 seconds to solve the equation, and here we go Genearl equation of parabola is: y=ax^2+bx+c Vertex (2,0) and point is (0,3) now put point(0,3) in equation and find the value of c i.e c=3 now find the value of a and b put vertex in the equation this time and you will get 4a+2b+3=0 ----1 also x cordinate will be x= -b/2a put the vertex(2,0) 2=-b/2a find the relation ship between b and a and put it in equation 1 to find the value of b and a i.e. b=-3 and 3/4

finally use original equation y=3/4x^2-3x+3---2 put x=3 and find the value of y which will be .75

Round it off and u will get 1..

In my opinion, it will be the most reliable way to solve this question by writing the equation of parabola, however it take around a minute to get to solution..

i think if such a question does appear on the GMAT, I will not have very close options. If somebody says the answer is .60, we won't argue and if somebody says it is .70 , again we won't argue. Therefore answer choices will be straight forward, something like A) 1 , B)-1 , C)0, D) 2 , E) -2.

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