Graph problem : PS Archive
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Graph problem

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Intern
Joined: 19 Oct 2009
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09 Nov 2009, 14:13
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Question Stats:

50% (01:30) correct 50% (00:58) wrong based on 3 sessions

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2. According to the graph below, when x = 3, y most nearly ?
(A) –1
(B)
(C) 0
(D)
(E) 1
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Senior Manager
Joined: 18 Aug 2009
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09 Nov 2009, 18:14
gmat620 wrote:
2. According to the graph below, when x = 3, y most nearly ?
(A) –1
(B)
(C) 0
(D)
(E) 1

With the given options, E?
From the graph, y=3,x=0, y=0,x=2, so if it is symmetric, y=3,x=4. And for x=3,y=1.5 (rounded off to 2, but 2 is not one of the options). is it a official prep Q?
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10 Nov 2009, 00:37
yes it is one of the retired question. I don't get what GMAT wants to calculate here. Can anyone provide the right approach ?
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10 Nov 2009, 03:07
how on earth it can -1 ? its between 1/2 and 1. I am confused between these two. Not sure how to zero-in.
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10 Nov 2009, 04:31
Sorry mate; completely forgot that it is a parabolic equation..
In my opinion it will take at least 90 seconds to solve the equation, and here we go
Genearl equation of parabola is: y=ax^2+bx+c
Vertex (2,0) and point is (0,3)
now put point(0,3) in equation and find the value of c i.e c=3
now find the value of a and b
put vertex in the equation this time and you will get
4a+2b+3=0 ----1
also x cordinate will be
x= -b/2a put the vertex(2,0)
2=-b/2a find the relation ship between b and a and put it in equation 1 to find the value of b and a i.e. b=-3 and 3/4

finally use original equation
y=3/4x^2-3x+3---2
put x=3 and find the value of y which will be .75

Round it off and u will get 1..

In my opinion, it will be the most reliable way to solve this question by writing the equation of parabola, however it take around a minute to get to solution..

good luck
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10 Nov 2009, 08:22
i think if such a question does appear on the GMAT, I will not have very close options. If somebody says the answer is .60, we won't argue and if somebody says it is .70 , again we won't argue. Therefore answer choices will be straight forward, something like A) 1 , B)-1 , C)0, D) 2 , E) -2.
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12 Nov 2009, 08:32
this curve has (x-2)² for equation... then answer is 1(E)
Re: Graph problem   [#permalink] 12 Nov 2009, 08:32
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