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On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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30 Jul 2012, 01:53
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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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30 Jul 2012, 01:54
SOLUTIONOn the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =(A) 1 (B) 1/2 (C) 0 (D) 1/2 (E) 1 Since the graph is symmetric with respect to line \(x = 2\), then the value of \(y\) when \(x = 3\) will be the same as the value of \(y\) when \(x = 1\), so 1. Answer: E.
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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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30 Jul 2012, 02:18
(E) 1
its symmetric with respect to x=2. when x=1, 1 unit to the left of x(2), y is 1. when x=3, 1 unit to the right of x(2), y should again be 1 as it is symmetric.



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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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02 Jan 2013, 07:18
Bunuel wrote: Attachment: Graph.png On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y = (A) 1 (B) 1/2 (C) 0 (D) 1/2 (E) 1 Half of the entire graph is a mirror image of the other side. The center coordinate is (2,0) according to the graph. Thus, y when x=1 and y when x3 are equal. Answer: E
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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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09 Sep 2014, 11:12
Bunuel wrote: Attachment: Graph.png On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y = (A) 1 (B) 1/2 (C) 0 (D) 1/2 (E) 1 Practice Questions Question: 7 Page: 153 Difficulty: 600 graph is symmetric with respect to the vertical line so if x = 1, y = 1 & x=2 , y=0 then x=3 , y=1 ...



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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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19 May 2016, 10:24
Bunuel wrote: Attachment: Graph.png On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y = (A) 1 (B) 1/2 (C) 0 (D) 1/2 (E) 1 We are given that the graph is SYMMETRIC along the vertical line x = 2. We are also given that when x = 1, y = 1. We are asked to determine the value of y when x is 3. Keep in mind that when x = 1, it is ONE UNIT away from the line x = 2, and when x = 3, it is also ONE UNIT away from the line x = 2. Since the ycoordinate is 1, when x is 1, the ycoordinate is ALSO 1 when x is 3. Again, this is because the graph is symmetric with the line x = 2. Another way to look at this problem is to see that the point (1,1) is actually being reflected over the line x = 2. We see that the point (1,1) is exactly 1 unit from the line x = 2. In fact the point (2,1) is on the line x = 2 which is exactly 1 unit from (1,1). However, (1,1) is exactly 1 unit on the LEFT of (2,1), so by symmetry, the point that is exactly 1 unit on the RIGHT of (2,1) is (3,1). Thus the ycoordinate is 1. Answer E.
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On the graph above, when x = 1/2, y = 2; and when x = 1, y =
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07 Oct 2017, 14:10
Bunuel wrote: On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y = (A) 1 (B) 1/2 (C) 0 (D) 1/2 (E) 1 We're told that the graph of the parabola is symmetric with respect to the vertical line at x = 2 So, for example, notice that the point (0,3) lies on the parabola. This point is 2 units to the LEFT of the line of symmetry. This means that there's also a point that is 2 units to the RIGHT of the line of symmetry. So, the coordinates of that point are (4,3)Likewise, we're told that the point (1,1) lies on the parabola. This point is 1 unit to the LEFT of the line of symmetry. This means that there's also a point that is 1 unit to the RIGHT of the line of symmetry. So, the coordinates of that point are (3,1)Answer: E Cheers, Brent
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On the graph above, when x = 1/2, y = 2; and when x = 1, y = &nbs
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