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Math Expert V
Joined: 02 Sep 2009
Posts: 58100
On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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5
30 00:00

Difficulty:   5% (low)

Question Stats: 84% (01:02) correct 16% (01:36) wrong based on 2058 sessions

### HideShow timer Statistics On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

Practice Questions
Question: 7
Page: 153
Difficulty: 600

Attachment: Graph.png [ 6.01 KiB | Viewed 38575 times ]

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Math Expert V
Joined: 02 Sep 2009
Posts: 58100
Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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3
7
SOLUTION On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

Since the graph is symmetric with respect to line $$x = 2$$, then the value of $$y$$ when $$x = 3$$ will be the same as the value of $$y$$ when $$x = 1$$, so 1.

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##### General Discussion
Intern  Joined: 27 Jul 2012
Posts: 25
Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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(E) 1

its symmetric with respect to x=2.
when x=1, 1 unit to the left of x(2), y is 1.
when x=3, 1 unit to the right of x(2), y should again be 1 as it is symmetric.
Senior Manager  Joined: 13 Aug 2012
Posts: 405
Concentration: Marketing, Finance
GPA: 3.23
Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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1
Bunuel wrote:
Attachment:
Graph.png

On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

Half of the entire graph is a mirror image of the other side. The center coordinate is (2,0) according to the graph. Thus, y when x=1 and y when x-3 are equal.

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Impossible is nothing to God.
Manager  Joined: 07 Apr 2014
Posts: 102
Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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1
Bunuel wrote:
Attachment:
Graph.png
On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

Practice Questions
Question: 7
Page: 153
Difficulty: 600

graph is symmetric with respect to the vertical line

so if x = 1, y = 1 & x=2 , y=0 then x=3 , y=1 ...
Target Test Prep Representative G
Status: Head GMAT Instructor
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2819
Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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6
Bunuel wrote:
Attachment:
Graph.png
On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

We are given that the graph is SYMMETRIC along the vertical line x = 2. We are also given that when x = 1, y = 1. We are asked to determine the value of y when x is 3. Keep in mind that when x = 1, it is ONE UNIT away from the line x = 2, and when x = 3, it is also ONE UNIT away from the line x = 2.

Since the y-coordinate is 1, when x is 1, the y-coordinate is ALSO 1 when x is 3. Again, this is because the graph is symmetric with the line x = 2.

Another way to look at this problem is to see that the point (1,1) is actually being reflected over the line x = 2.

We see that the point (1,1) is exactly 1 unit from the line x = 2. In fact the point (2,1) is on the line x = 2 which is exactly 1 unit from (1,1). However, (1,1) is exactly 1 unit on the LEFT of (2,1), so by symmetry, the point that is exactly 1 unit on the RIGHT of (2,1) is (3,1). Thus the y-coordinate is 1.

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CEO  V
Joined: 12 Sep 2015
Posts: 3961
On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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Top Contributor
3
Bunuel wrote: On the graph above, when x = 1/2, y = 2; and when x = 1, y = 1. The graph is symmetric with respect to the vertical line at x = 2. According to the graph, when x = 3, y =

(A) -1
(B) -1/2
(C) 0
(D) 1/2
(E) 1

We're told that the graph of the parabola is symmetric with respect to the vertical line at x = 2
So, for example, notice that the point (0,3) lies on the parabola.
This point is 2 units to the LEFT of the line of symmetry. This means that there's also a point that is 2 units to the RIGHT of the line of symmetry.
So, the coordinates of that point are (4,3) Likewise, we're told that the point (1,1) lies on the parabola.
This point is 1 unit to the LEFT of the line of symmetry. This means that there's also a point that is 1 unit to the RIGHT of the line of symmetry.
So, the coordinates of that point are (3,1) Cheers,
Brent
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Re: On the graph above, when x = 1/2, y = 2; and when x = 1, y =  [#permalink]

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# On the graph above, when x = 1/2, y = 2; and when x = 1, y =

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