Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Can anybody chime in? Although I agree with the answer, I don't think the bold statement below is correct. B does not have to be 0 or greater. It can be -4 if A is 1.

If b= -4 and a=1. this satisfiies the conditions: 1) a,b are integers 2) a is not equal to b 3) statement 2; 1^(-4)=1. that is a non-zero integer. So you can't say B is definitely positive or 0. Combining statement 1 and 2. You can't determine if A is a 1 or not so E.

Please correct me if I am wrong. Thanks.

Fig wrote:

(E) for me.

|a|*b > 0 ? <=> b > 0 ?

From (1) |a^b| > 0

o If b=-1 and a=1, 1 > 0 and b < 0 o If b=1 and a=-1, 1 > 0 and b > 0

INSUFF.

[b]From (2) |a|^b is a non zero integer implies that b must be positive or equal to 0 in order to not create a real number such as 2^-1.

So, we remains with the cases of b = 0 and b > 0.[/b] INSUFF.

Re: DS_If a and b.... [#permalink]
26 Nov 2009, 19:34

mm007 wrote:

If a and b are integers, and a not= b, is |a|b > 0?

(1) |a^b| > 0

(2) |a|^b is a non-zero integer

Clearly E. |a^b| and |a|^b are always >0, no matter what b is, because absolute value is always greater than 0. Thus, we can't know if b>0 or not. _________________

Re: DS_If a and b.... [#permalink]
21 Dec 2009, 08:22

mm007 wrote:

If a and b are integers, and a not= b, is |a|b > 0?

(1) |a^b| > 0

(2) |a|^b is a non-zero integer

Question is |a|b>0 this can be proved if we can prove that a not=0 and b>0. 1. |a^b| > 0 implies that a not = 0. a can be +ve or -ve, and be can be 0, +ve or -ve....but we are sure that a not=0 else |a^b| = 0. Statement 1 itself is insuff.

2. |a|^b is a non zero integer. we already know a,b both are integers....|a| is > 0, so b >= 0. No clear value of b...

Given: a , b are ints. and a is different from b asking: |a| * b > 0

what the question is really asking if b > 0 [ |a| is always >0 ]

(1) |a^b| >0 ---------------- says nothing, cuz |x| is always > 0 statement 1 is insufficient

(2) |a|^b is not zero ------------------------- also says nothing .. we know |a|^b > 0 b could be -ve or +ve statement 2 is insufficient

(1) and (2) together ------------------------ both statements really say nothing about b

final answer is E

>>Please tell me how can |a| be taken as positive in the above steps without knowing its sign..I mean if a is negative,then |a| wil be negative..Right?Am i missing anythin badly?

>>Please tell me how can |a| be taken as positive in the above steps without knowing its sign..I mean if a is negative,then |a| wil be negative..Right?Am i missing anythin badly?

Absolute value of of an expression is alway non-negative: |some \ expression|\geq{0}. Please check Walker's post on Absolute Value at: math-absolute-value-modulus-86462.html

As for the question:

If a and b are integers, and a does not equal to b, is |a|*b > 0? (1) |a^b| > 0 (2) |a|^b is a non-zero integer.

|a|*b>0 is true when b>0 and a does not equal to zero.

(1) |a^b| > 0 --> a does not equal to zero, but we don't know about b, it can be any value, positive or negative. Not sufficient.

(2) |a|^b is a non-zero integer --> a can be 1 and b any integer, positive or negative. Not sufficient.

(1)+(2) If a=1 and b=2, then |a|*b>0, but if a=1 and b=-2, then |a|*b<0. Not sufficient.

Re: DS question : need help [#permalink]
28 Oct 2010, 18:20

Basically just need to find out if b is positive or negative, since a will always be positive as it is inside of the | |.

1) Doesn't give you anything because everything is inside of the | |, so you can't tell if b is positive or negative, so insufficient.

2) Tells you that b is not negative since that would result in a non-integer. However, b could be 0 since a number raised to the 0 is 1, which is a non-integer number. Also insufficient.

Using both statements still doesn't provide anything because b can still be equal to 0, in which case |a|b > 0 is false. However, b can also be any positive number which would make |a|b > 0 true. Thus E.

Re: If a and b are integers, and a not= b, is |a|b > 0? (1) [#permalink]
04 Jun 2014, 18:35

The reason why s2 alone or taken together with s1 is not sufficient bcos we need info on the signs that is, a is +ve or -ve and whether b is +ve or -ve & not wether they are zero or non-zero integers.

Re: If a and b are integers, and a not= b, is |a|b > 0? (1) [#permalink]
02 Sep 2014, 03:43

Bunuel wrote:

ravitejapandiri wrote:

>>Please tell me how can |a| be taken as positive in the above steps without knowing its sign..I mean if a is negative,then |a| wil be negative..Right?Am i missing anythin badly?

Absolute value of of an expression is alway non-negative: |some \ expression|\geq{0}. Please check Walker's post on Absolute Value at: math-absolute-value-modulus-86462.html

As for the question:

If a and b are integers, and a does not equal to b, is |a|*b > 0? (1) |a^b| > 0 (2) |a|^b is a non-zero integer.

|a|*b>0 is true when b>0 and a does not equal to zero.

(1) |a^b| > 0 --> a does not equal to zero, but we don't know about b, it can be any value, positive or negative. Not sufficient.

(2) |a|^b is a non-zero integer --> a can be 1 and b any integer, positive or negative. Not sufficient.

(1)+(2) If a=1 and b=2, then |a|*b>0, but if a=1 and b=-2, then |a|*b<0. Not sufficient.

If a and b are integers, and a not= b, is |a|b > 0? (1) [#permalink]
02 Sep 2014, 03:49

1

This post received KUDOS

Expert's post

shahPranay14 wrote:

Bunuel wrote:

ravitejapandiri wrote:

>>Please tell me how can |a| be taken as positive in the above steps without knowing its sign..I mean if a is negative,then |a| wil be negative..Right?Am i missing anythin badly?

Absolute value of of an expression is alway non-negative: |some \ expression|\geq{0}. Please check Walker's post on Absolute Value at: math-absolute-value-modulus-86462.html

As for the question:

If a and b are integers, and a does not equal to b, is |a|*b > 0? (1) |a^b| > 0 (2) |a|^b is a non-zero integer.

|a|*b>0 is true when b>0 and a does not equal to zero.

(1) |a^b| > 0 --> a does not equal to zero, but we don't know about b, it can be any value, positive or negative. Not sufficient.

(2) |a|^b is a non-zero integer --> a can be 1 and b any integer, positive or negative. Not sufficient.

(1)+(2) If a=1 and b=2, then |a|*b>0, but if a=1 and b=-2, then |a|*b<0. Not sufficient.