Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Can anybody chime in? Although I agree with the answer, I don't think the bold statement below is correct. B does not have to be 0 or greater. It can be -4 if A is 1.
If b= -4 and a=1. this satisfiies the conditions: 1) a,b are integers 2) a is not equal to b 3) statement 2; 1^(-4)=1. that is a non-zero integer. So you can't say B is definitely positive or 0. Combining statement 1 and 2. You can't determine if A is a 1 or not so E.
Please correct me if I am wrong. Thanks.
(E) for me.
|a|*b > 0 ? <=> b > 0 ?
From (1) |a^b| > 0
o If b=-1 and a=1, 1 > 0 and b < 0 o If b=1 and a=-1, 1 > 0 and b > 0
[b]From (2) |a|^b is a non zero integer implies that b must be positive or equal to 0 in order to not create a real number such as 2^-1.
So, we remains with the cases of b = 0 and b > 0.[/b] INSUFF.
Re: DS_If a and b.... [#permalink]
21 Dec 2009, 08:22
If a and b are integers, and a not= b, is |a|b > 0?
(1) |a^b| > 0
(2) |a|^b is a non-zero integer
Question is |a|b>0 this can be proved if we can prove that a not=0 and b>0. 1. |a^b| > 0 implies that a not = 0. a can be +ve or -ve, and be can be 0, +ve or -ve....but we are sure that a not=0 else |a^b| = 0. Statement 1 itself is insuff.
2. |a|^b is a non zero integer. we already know a,b both are integers....|a| is > 0, so b >= 0. No clear value of b...
Re: DS question : need help [#permalink]
28 Oct 2010, 18:20
Basically just need to find out if b is positive or negative, since a will always be positive as it is inside of the | |.
1) Doesn't give you anything because everything is inside of the | |, so you can't tell if b is positive or negative, so insufficient.
2) Tells you that b is not negative since that would result in a non-integer. However, b could be 0 since a number raised to the 0 is 1, which is a non-integer number. Also insufficient.
Using both statements still doesn't provide anything because b can still be equal to 0, in which case |a|b > 0 is false. However, b can also be any positive number which would make |a|b > 0 true. Thus E.
Re: DS question : need help
28 Oct 2010, 18:20