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M12 Q32

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Re: M12 Q32 [#permalink]

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New post 06 Jun 2014, 09:42
sunita123 wrote:
Hi Bunuel,
I have a question here,
so when you considered both the statement and got x^3*y^4 = 5^3*2^4=2000.
i want to know how you reached there? did you try plugging in x=1 ,2, 3 , 4 and 5 and y =1 , 2 etc?just trying to understand the thought process . when i tried to take both the statements i could not do that .

Bunuel wrote:
echizen wrote:
If \(x^3*y^4 = 2000\), what is \(y\)?

1. \(x\) is an integer
2. \(y\) is an integer

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If \(x^3*y^4 = 2000\), what is \(y\)?

(1) \(x\) is an integer.
(2) \(y\) is an integer.

Each statement alone is insufficient. When considering together we have: \(x^3*y^4 = 5^3*2^4=2000\), but since \(y\) is in even power it can be 2 as well as -2. Not sufficient.

Answer: E.

Do you mean how I got 5^3*2^4? I made prime factorization of 2,000:

\(2,000 = 16*125 = 2^4*5^3\).

Hope it's clear.

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Re: M12 Q32   [#permalink] 06 Jun 2014, 09:42

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