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34% (01:10) correct 66% (01:16) wrong based on 144 sessions
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15 Sep 2014, 23:48



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04 Aug 2016, 04:12
I think this is a highquality question and I agree with explanation.



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15 Aug 2016, 04:12
I think this is a highquality question and I agree with explanation. good question



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30 Aug 2016, 06:21
great question, so tricky



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09 Sep 2016, 05:26
Bunuel wrote: Official Solution:
Each statement alone is insufficient. When considering them together we have: \(x^3*y^4 = 5^3*2^4=2000\), but since \(y\) is in even power, it can be 2 as well as 2. Not sufficient.
Answer: E Thanks for the explanation, Banuel. Do you happen to know the source of the question?



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09 Sep 2016, 06:30
Bunuel wrote: Official Solution:
Each statement alone is insufficient. When considering them together we have: \(x^3*y^4 = 5^3*2^4=2000\), but since \(y\) is in even power, it can be 2 as well as 2. Not sufficient.
Answer: E Hi Bunuel! could you please expand your explanation? I don't understand why A and B are not sufficient alone.



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09 Sep 2016, 06:53
No matter what x is, y could be positive or negative. Unless we get more information on y's sign, we can't know the answer. y being an integer doesn't tell us its sign.



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06 Oct 2016, 12:40
Can anyone show the insufficiency for Statement A and B individually?



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06 Oct 2016, 23:42



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Re: M1232
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08 Nov 2016, 03:39
Hello,
In statement no. 2 , y^4= 2000/ x^3
Here x should be 5,
So, y^4=2^4
y should be 2 as per GMAT rules as root value is always taken as positive.
What is wrong with my analysis.



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08 Nov 2016, 03:50
Sumanth8492 wrote: Hello,
In statement no. 2 , y^4= 2000/ x^3
Here x should be 5,
So, y^4=2^4
y should be 2 as per GMAT rules as root value is always taken as positive.
What is wrong with my analysis. y^4 = 16 This means y=2 or 2 only!



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08 Nov 2016, 05:40
Sumanth8492 wrote: Hello,
In statement no. 2 , y^4= 2000/ x^3
Here x should be 5,
So, y^4=2^4
y should be 2 as per GMAT rules as root value is always taken as positive.
What is wrong with my analysis. When the GMAT provides the square root sign for an even root, such as \(\sqrt{x}\) or \(\sqrt[4]{x}\), then the only accepted answer is the positive root. That is, \(\sqrt{16}=4\), NOT +4 or 4. Even roots have only a positive value on the GMAT. Odd roots have the same sign as the base of the root. For example, \(\sqrt[3]{125} =5\) and \(\sqrt[3]{64} =4\). In contrast, the equation \(x^2=16\) has TWO solutions, +4 and 4.
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How do you determine that x is 5 and y is 2? Trial and error?



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05 Jan 2017, 09:37
Great Question!!



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07 May 2017, 09:34
Great question



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11 Jun 2017, 01:15
BunuelDoes it matter if x & y are integers or not in this type of question (not this question in particular, but this type of question). Let's assume the question states that x & y are both positive, does it make a difference if the question does not specify that x & y are integers? Thanks!



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12 Jun 2017, 03:29



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14 Jun 2017, 20:02
Superb question! Easy to forget that 2 and 2 both have to be considered.







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