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Re: If 1/Q > 1, which of the following must be true? [#permalink]
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If \(\frac{1}{Q} > 1\), which of the following must be true?

(A) \(1 < Q^2\)

(B) \(\frac{1}{Q^2} > 2\)

(C) \(1 > Q^2\)

(D) \(\frac{1}{Q^2} < 1\)

(E) \(Q < Q^2\)

\(\frac{1}{Q} > 1\) is only possible when 0 < Q < 1
This implies that Q^2 < Q < 1(Here we can go with C straight but let's check other choices).

Thus, A, D(same as A) and E are out straight. 
B is wrong since
\(1 < \frac{1}{Q^2} < infinity\)
Hence either possibility exists.

Answer C.
 
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If 1/Q > 1, which of the following must be true? [#permalink]
1/q - 1 >0
hence , (1-q)/ q > 0
either (1-q ) > 0 and q > 0 ; Hence , 0<q<1

or (1-q) < 0 and q < 0 ..this scenario is impossible.

Hence , q is between 0 and 1 . Say q = 1/2 , then q^2 = 1/4
Hence we can say that q^2 < 1 ..C is the answer.­ gmatophobia
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Re: If 1/Q > 1, which of the following must be true? [#permalink]
mayankdgmat wrote:
Bunuel I am getting Q>Q2. is there a typo in (E)?­

­I think if Q is negative then this still holds true which cannot be the case!
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Re: If 1/Q > 1, which of the following must be true? [#permalink]
Expert Reply
K-ja wrote:
mayankdgmat wrote:
­If \(\frac{1}{Q} > 1\), which of the following must be true?

(A) \(1 < Q^2\)

(B) \(\frac{1}{Q^2} > 2\)

(C) \(1 > Q^2\)

(D) \(\frac{1}{Q^2} < 1\)

(E) \(Q < Q^2\)

Bunuel I am getting Q>Q2. is there a typo in (E)?­

­I think if Q is negative then this still holds true which cannot be the case!

Q cannot be negative because \(\frac{1}{Q} > 1\) implies \(0 < Q < 1\). Next, E is not correct because \(Q < Q^2\) is not true for any of the values from \(0 < Q < 1\). Or to put it in another way, since \(0 < Q < 1\), then 0 < Q^2 < Q, so Q < Q^2 is not true.­
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Re: If 1/Q > 1, which of the following must be true? [#permalink]
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