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Ok.. Let's start by turning the exponents into positive ones

(.08)^-4/(.04)^-3 = (.04)^3/(.08)^4

Notice that: (.04)^3 = (4/100)^3 = 4^3/100^3
also (.08)^4 = (8/100)^4 = 8^4/100^4

So the expression becomes: 4^3*100^4/8^4*100^3 = (2^2)^3*100/(2^3)^4 = 2^6*100/2^12 = 100/2^6 = 2^2*5^2/2^6 = 5^2/2^4 = 25/16

The answer is "C"

Gooood luck!
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What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?
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Konstantin1983
What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?

The numerator is (0.08)^-3, so if you take 2 as common, you need to include the power to 2 as well.

As in, (p*q)^n = p^n * q^n
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abhimahna
Konstantin1983
What am i doing wrong?

(0.08)=2*0.04 Hence we can write this expression as 2((0.04)^-4)/(0.04^-3) Since we have division here we can write this as (0.04^-1) right? Hence we have 2*(100/4)=50 What is wrong? Please help?

The numerator is (0.08)^-3, so if you take 2 as common, you need to include the power to 2 as well.

As in, (p*q)^n = p^n * q^n

Oh yeah right Abhimahna) Stupid mistake!
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