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Bunuel
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NischalSR ZenJames

If someone can lease exlain me where am I going wrong,
For A, I started w dividing the question with 0.5 throughout so it was x^7>y^5>z^3 if we take y as 2 and z as 3 then this condition is satisfied 32 (i.e 2^5)>27 (i.e 3^3) but 2>3 is not satisfied hence A cannot be true
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Dhwanii

I think you are stopping at testing just one case. I took the theoretical approach instead, but I reckon you can do both.
The question is asking "which of the following CANNOT be true" meaning that there is no way that it can be true.
Consider this for option A: if x=3, y=2 , z=1, then A is true.
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ZenJames, Thanks for your help. Understood, so basically even if one value can be true, option has to be discarded. Guess I used the must be true approach.
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What set of numbers can both be true for option C and the original question? In other words, how can we eliminate option C?
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Since the exponents are in decimal form, 3.5 can be expressed as 7/2, representing the square root of x raised to the 7th power. Therefore, x cannot be negative, as the square root of a negative number is not defined.

similarly, x, y , and z are positive (0 is also not possible)

Now, we can take any power of the inequality as both sides of the inequality are non-negative.

If you take the square of the given inequality, you will get x^7>y^5> z^3

whereas the given relation in D is the opposite of this and hence NOT Possible.

D is the right answer.

Bunuel
If \(x^{3.5} > y^{2.5} > z^{1.5}\), then which of the following cannot be true?

(A) \(x > y > z\)

(B) \(x < y < z\)

(C) \(x^3 < y^2 < z\)

(D) \(x^7 < y^5 < z^3\)

(E) \(x^{10.5} > y^{7.5} > z^{4.5}\)
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