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Re: (1/2+1/3)/(1/4) = [#permalink]
carcass wrote:
\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}=\) ?


A) \(\frac{1}{12}\)

B) \(\frac{5}{24}\)

C) \(\frac{2}{3}\)

D) \(\frac{3}{4}\)

E) \(\frac{10}{3}\)


\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}= 4(\frac{5}{6}) = \frac{10}{3}\). Ans - E.
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(1/2+1/3)/(1/4) = [#permalink]
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carcass wrote:
\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}=\) ?


A) \(\frac{1}{12}\)

B) \(\frac{5}{24}\)

C) \(\frac{2}{3}\)

D) \(\frac{3}{4}\)

E) \(\frac{10}{3}\)


Here's an approach that uses approximation

Given: (1/2 + 1/3)/(1/4)

1/2 + 1/3 = a little less than 1 so we can write: (a little less than 1)/(1/4)

We know that 1/(1/4) = 4

So, (a little less than 1)/(1/4) = a little less than 4

Since only one answer choice (E) is greater than 1, it is the ONLY answer choice that's reasonably close to a little less than 4

Originally posted by BrentGMATPrepNow on 22 Jun 2017, 07:10.
Last edited by BrentGMATPrepNow on 26 Sep 2020, 07:33, edited 1 time in total.
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Re: (1/2+1/3)/(1/4) = [#permalink]
Expert Reply
carcass wrote:
\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}=\) ?


A) \(\frac{1}{12}\)

B) \(\frac{5}{24}\)

C) \(\frac{2}{3}\)

D) \(\frac{3}{4}\)

E) \(\frac{10}{3}\)


We can multiply the given expression by 12/12 and we have:

(6 + 4)/3 = 10/3

Answer: E
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Re: (1/2+1/3)/(1/4) = [#permalink]
carcass wrote:
\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}=\) ?


A) \(\frac{1}{12}\)

B) \(\frac{5}{24}\)

C) \(\frac{2}{3}\)

D) \(\frac{3}{4}\)

E) \(\frac{10}{3}\)

\(\frac{\frac{1}{2} + \frac{1}{3}}{\frac{1}{4}}\)

= \(\frac{\frac{5}{6}}{\frac{1}{4}}\)

\(= \frac{5}{6} *\frac{4}{1}\)

\(= \frac{10}{3}\), Answer is (E)
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Re: (1/2+1/3)/(1/4) = [#permalink]
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Re: (1/2+1/3)/(1/4) = [#permalink]
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