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(3508)^2 - (3510*3508) =

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(3508)^2 - (3510*3508) =  [#permalink]

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New post 18 Feb 2018, 22:00
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

91% (01:00) correct 9% (01:18) wrong based on 148 sessions

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Re: (3508)^2 - (3510*3508) =  [#permalink]

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New post 18 Feb 2018, 22:25
1
Bunuel wrote:
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


Just straight-forward solving the eqauation

(3508)^2 - (3510*3508) = (3508)(3508 - 3510) = 3508 * (-2) = -7016(Option E)
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Re: (3508)^2 - (3510*3508) =  [#permalink]

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New post 23 Feb 2018, 05:32
1
1
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


From the question we can make out the answer is going to be -ve.
1,2,3 not possible.
if is going to be D: then the value which you are substracting should be greater than one ((3508)^2 - (3509 * 3508)) but it is not. So eliminating D.
So the answer is E

Kudos appreciated.
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Re: (3508)^2 - (3510*3508) =  [#permalink]

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New post 23 Feb 2018, 08:37
Top Contributor
Bunuel wrote:
(3508)² - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


This calls for some factoring

(3508)² - (3510*3508) = (3508)(3508) - (3510)(3508)
= 3508(3508 - 3510)
= 3508(-2)
= -7016

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Re: (3508)^2 - (3510*3508) =  [#permalink]

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New post 23 Feb 2018, 08:42
Top Contributor
Bunuel wrote:
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


Another approach is to keep track of the units digits only

(3508)² - (3510*3508) = (---6) - (---0)
= ----6

Since answer choice E is the only answer with units digit 6, E must be correct.

Cheers,
Brent
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Re: (3508)^2 - (3510*3508) =  [#permalink]

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New post 18 Mar 2018, 06:19
Bunuel wrote:
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


(3508)^2 - (3510*3508) = ?

3508 * (3508 - 3510)

3508 * (-2)

-7016

(E)
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Re: (3508)^2 - (3510*3508) = &nbs [#permalink] 18 Mar 2018, 06:19
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