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Sub 505 (Easy)|   Algebra|   Arithmetic|      
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Bunuel
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(3508)^2 - (3510*3508) = 18 Feb 2018, 23:00
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

5% (low)

Question Stats:

82% (00:56) correct 18% (01:11) wrong based on 356 sessions

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(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
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E
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(3508)^2 - (3510*3508) = 18 Feb 2018, 23:25
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Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

Just straight-forward solving the eqauation

(3508)^2 - (3510*3508) = (3508)(3508 - 3510) = 3508 * (-2) = -7016(Option E)
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(3508)^2 - (3510*3508) = 23 Feb 2018, 06:32
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(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016


From the question we can make out the answer is going to be -ve.
1,2,3 not possible.
if is going to be D: then the value which you are substracting should be greater than one ((3508)^2 - (3509 * 3508)) but it is not. So eliminating D.
So the answer is E

Kudos appreciated.
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(3508)^2 - (3510*3508) = Updated on: 01 Jun 2020, 09:32
Originally posted by BrentGMATPrepNow on 23 Feb 2018, 09:37.
Last edited by BrentGMATPrepNow on 01 Jun 2020, 09:32, edited 1 time in total.
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Bunuel
(3508)² - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

This calls for some factoring

(3508)² - (3510*3508) = (3508)(3508) - (3510)(3508)
= 3508(3508 - 3510)
= 3508(-2)
= -7016

Answer: E
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(3508)^2 - (3510*3508) = Updated on: 10 Apr 2021, 06:26
Originally posted by BrentGMATPrepNow on 23 Feb 2018, 09:42.
Last edited by BrentGMATPrepNow on 10 Apr 2021, 06:26, edited 2 times in total.
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Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

Another approach is to keep track of the units digits only

(3508)² - (3510*3508) = (---6) - (---0)
= -(----4)

Since answer choice E is the only answer with units digit 4, E must be correct.

Cheers,
Brent
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(3508)^2 - (3510*3508) = 18 Mar 2018, 07:19
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Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

(3508)^2 - (3510*3508) = ?

3508 * (3508 - 3510)

3508 * (-2)

-7016

(E)
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(3508)^2 - (3510*3508) = 29 Aug 2019, 10:58
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Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

Let a = 3508 & b = 3510 Or, (a + 2)

So, (3508)^2 - (3510*3508) = a^2 - ab

Or, a^2 - ab = a ( a - b)

Or, a ( a - b) = a (a - a - 2)

Or, a ( a - b) = -2a

THus, Answer must be -2*3508 = -7016 , Answer must be (E)
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(3508)^2 - (3510*3508) = 03 Sep 2019, 07:03
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Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016
Show more

Factor 3508 from both terms, obtaining:

3508(3508 - 3510)

3508(-2) = -7016

Answer: E
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(3508)^2 - (3510*3508) = 10 Apr 2021, 04:42
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BrentGMATPrepNow
Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016

Another approach is to keep track of the units digits only

(3508)² - (3510*3508) = (---6) - (---0)
= ----6

Since answer choice E is the only answer with units digit 6, E must be correct.

Cheers,
Brent
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Please could you help me understand how to calculate units place here? I tried solving through this method I am getting units place as 4
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(3508)^2 - (3510*3508) = 10 Apr 2021, 06:26
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PoojaKGandhi
BrentGMATPrepNow
Bunuel
(3508)^2 - (3510*3508) =

(A) 7020

(B) 0

(C) -2

(D) -3508

(E) -7016

Another approach is to keep track of the units digits only

(3508)² - (3510*3508) = (---4) - (---0)
= -(----4)

Since answer choice E is the only answer with units digit 6, E must be correct.

Cheers,
Brent



Please could you help me understand how to calculate units place here? I tried solving through this method I am getting units place as 4
Show more

Oops, I made a mistake earlier (which I've corrected in the highlighted area above )

When multiplying two integers, the units digit of the entire product will be the same as the units digit of the product of the two units digits.
For example, we know that (7)(2) = 14
This means the product of something like (327)(122) will be -------4

Likewise, the units digit of 3508*3508 will be the unit's digit of (8)(8), which is 4
And the units digit of 3510*3508 will be the unit's digit of (0)(8), which is 0

So, we have (3508)² - (3510*3508) = (---4) - (---0)

Finally we need to recognize that (3508)² < (3510*3508)
So, when we subtract (3510*3508) from (3508)², we will get a NEGATIVE result.
To determine the units digit of this negative result, you can test two values, such that the first number has units digit 4, and the second number has units digit 0 (where the second number is bigger)

For example you could try 4 - 10 = -6 (units digit 6)
Or 4 - 30 = -26 (units digit 6)
Or 24 - 100 = -76 (units digit 6)
Etc
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(3508)^2 - (3510*3508) = 11 Apr 2021, 02:58
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BrentGMATPrepNow
PoojaKGandhi
BrentGMATPrepNow




Another approach is to keep track of the units digits only

(3508)² - (3510*3508) = (---4) - (---0)
= -(----4)

Since answer choice E is the only answer with units digit 6, E must be correct.

Cheers,
Brent



Please could you help me understand how to calculate units place here? I tried solving through this method I am getting units place as 4

Oops, I made a mistake earlier (which I've corrected in the highlighted area above )

When multiplying two integers, the units digit of the entire product will be the same as the units digit of the product of the two units digits.
For example, we know that (7)(2) = 14
This means the product of something like (327)(122) will be -------4

Likewise, the units digit of 3508*3508 will be the unit's digit of (8)(8), which is 4
And the units digit of 3510*3508 will be the unit's digit of (0)(8), which is 0

So, we have (3508)² - (3510*3508) = (---4) - (---0)

Finally we need to recognize that (3508)² < (3510*3508)
So, when we subtract (3510*3508) from (3508)², we will get a NEGATIVE result.
To determine the units digit of this negative result, you can test two values, such that the first number has units digit 4, and the second number has units digit 0 (where the second number is bigger)

For example you could try 4 - 10 = -6 (units digit 6)
Or 4 - 30 = -26 (units digit 6)
Or 24 - 100 = -76 (units digit 6)
Etc
Show more



Thank you so much. Now I am understanding better :D
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(3508)^2 - (3510*3508) = 25 Feb 2024, 10:24
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