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# (5^(1/2) + 7^(1/2))^2 =

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Re: (5^(1/2) + 7^(1/2))^2 = [#permalink]
Bunuel wrote:
$$(\sqrt{5}+\sqrt{7})^2=$$

A. 12
B. $$12 + 2\sqrt{3}$$
C. $$12 + 4\sqrt{3}$$
D. $$12 + \sqrt{35}$$
E. $$12 + 2\sqrt{35}$$

Since (x + y)^2 = x^2 + y^2 + 2xy, we have:

(√5)^2 + (√7)^2 + 2(√5)(√7)

5 + 7 + 2√35

12 + 2√35

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Re: (5^(1/2) + 7^(1/2))^2 = [#permalink]
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Re: (5^(1/2) + 7^(1/2))^2 = [#permalink]
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