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A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln

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A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln  [#permalink]

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New post 14 Feb 2016, 02:53
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

78% (01:37) correct 22% (01:26) wrong based on 217 sessions

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A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln to Belnap. If the whole trip was 660 miles, how long did the round trip take?

A. 6 hours
B. 11 hours
C. 12.1 hours
D. 13.2 hours
E. 24.2 hours

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Re: A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln  [#permalink]

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New post 14 Feb 2016, 08:04
Bunuel wrote:
A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln to Belnap. If the whole trip was 660 miles, how long did the round trip take?

A. 6 hours
B. 11 hours
C. 12.1 hours
D. 13.2 hours
E. 24.2 hours


Whole trip was 660 miles. Which means one way trip was 330 miles.
Time taken from Belnap(B) to Lincoln(L)= 330/60 =5.5 hrs
Time taken from L to B = 330/50 = 6.6 hrs
Time spent on round trip: 6.6 + 5.5 = 12.1 hrs

Choice C.
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Re: A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln  [#permalink]

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New post 13 Nov 2017, 18:27
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Bunuel wrote:
A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln to Belnap. If the whole trip was 660 miles, how long did the round trip take?

A. 6 hours
B. 11 hours
C. 12.1 hours
D. 13.2 hours
E. 24.2 hours


Here's a quick solution.

Let's see what happens if the car traveled at the SAME SPEED for the entire 660 miles.

Time = distance/speed

IF the car traveled 60 mph for the entire 660 miles, then...
Travel time = 660/60 = 11 hours

Since the car traveled at a SLOWER speed of 50 mph for half of the trip, we can conclude that the entire trip took longer than 11 hours to complete
ELIMINATE A and B

IF the car traveled 50 mph for the entire 660 miles, then...
Travel time = 660/50 = 66/5 = 13.2 hours

ASIDE: There's a very fast way to quickly divide ANY number by 5 in your head (see the video below)

Since the car traveled at a FASTER speed of 60 mph for half of the trip, we can conclude that the entire trip took less than 13.2 hours to complete
ELIMINATE D and E

By the process of elimination, the correct answer must be C

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Re: A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln  [#permalink]

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New post 15 May 2018, 15:23
Bunuel wrote:
A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln to Belnap. If the whole trip was 660 miles, how long did the round trip take?

A. 6 hours
B. 11 hours
C. 12.1 hours
D. 13.2 hours
E. 24.2 hours



The time for the entire trip was:

330/60 + 330/50 = 33/6 + 33/5 = 11/2 + 33/5 = 55/10 + 66/10 = 121/10 = 12.1 hours

Answer: C
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A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln  [#permalink]

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New post 15 May 2018, 21:35
if the first half of distance is travelled at x speed and the rest half at y , the formula for average speed for the whole trip is

xy/(x+y)

so the average speed here is 50*60/(50+60) = 3000/110 = 300/11

Distance is 660 => time taken = 660/300/11 = 12.1

Answer: C
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A car traveled 60 mph from Belnap to Lincoln and 50 mph from Lincoln &nbs [#permalink] 15 May 2018, 21:35
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