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17 Sep 2007, 07:26
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
79% (01:03) correct
21%
(01:09)
wrong
based on 868
sessions
History
Date
Time
Result
Not Attempted Yet
A certain company divides its total advertising budget into television, radio, newspaper, and magazine budgets in the ratio of 8:7:3:2 respectively. How many dollars are in the radio budget?
(1) The television budget is $18,750 more than the newspaper budget
(2) The magazine budget is $7,500.
(1) The television budget is $18,750 more than the newspaper budget
(2) The magazine budget is $7,500.
General Discussion
17 Sep 2007, 09:31
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television ---> 8
radio ---> 7
newspaper ---> 3
magazine ---> 2
statement 1
television ---> 8 ---> 18,750+x or (x/3)*8
radio ---> 7 ---> (x/3)*7
newspaper ---> 3 ---> x
magazine ---> 2 ---> (x/3)*2
from that we can conclude that:
18,750+x = (x/3)*8
18,750*3+3*x = 8*x
(18,750*3)/5 = x
x = 11,250
radio ---> (x/3)*7 = 26,250
sufficient
statement 2
television ---> 8 ---> (7500/2)*8
radio ---> 7 ---> (7500/2)*7
newspaper ---> 3 ---> (7,500/2)*3
magazine ---> 2 ---> 7500/2
can be solved !
radio ---> (7500/2)*7 = 26,250
sufficient
the answer is (D)
radio ---> 7
newspaper ---> 3
magazine ---> 2
statement 1
television ---> 8 ---> 18,750+x or (x/3)*8
radio ---> 7 ---> (x/3)*7
newspaper ---> 3 ---> x
magazine ---> 2 ---> (x/3)*2
from that we can conclude that:
18,750+x = (x/3)*8
18,750*3+3*x = 8*x
(18,750*3)/5 = x
x = 11,250
radio ---> (x/3)*7 = 26,250
sufficient
statement 2
television ---> 8 ---> (7500/2)*8
radio ---> 7 ---> (7500/2)*7
newspaper ---> 3 ---> (7,500/2)*3
magazine ---> 2 ---> 7500/2
can be solved !
radio ---> (7500/2)*7 = 26,250
sufficient
the answer is (D)
