A certain company divides its total advertising budget into television, radio, newspaper, and magazine budgets in the ratio of 8:7:3:2 respectively. How many dollars are in the radio budget?

(1) The television budget is $18,750 more than the newspaper budget

(2) The magazine budget is $7,500.

television ---> 8
radio ---> 7
newspaper ---> 3
magazine ---> 2

statement 1

television ---> 8 ---> 18,750+x or (x/3)*8
radio ---> 7 ---> (x/3)*7
newspaper ---> 3 ---> x
magazine ---> 2 ---> (x/3)*2

from that we can conclude that:

18,750+x = (x/3)*8

18,750*3+3*x = 8*x

(18,750*3)/5 = x

x = 11,250

radio ---> (x/3)*7 = 26,250

sufficient

statement 2

television ---> 8 ---> (7500/2)*8
radio ---> 7 ---> (7500/2)*7
newspaper ---> 3 ---> (7,500/2)*3
magazine ---> 2 ---> 7500/2

can be solved !

radio ---> (7500/2)*7 = 26,250

sufficient

the answer is (D)

Hi GMATters,

Here's my video explanation of this problem:




Enjoy!

Rowan
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