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A college admissions officer predicts that 20 percent of the students

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targetbusiness
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A college admissions officer predicts that 20 percent of the students [#permalink] New post  10 Aug 2018, 00:22
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A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A. 1.05x
B. 1.1x
C. 1.2x
D. 1.25x
E. 1.8x
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Bunuel
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  10 Aug 2018, 00:33
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siddreal wrote:
A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

a)1.05x
b)1.1x
c)1.2x
d)1.25x
e)1.8x


(enrollment) = 0.8*(accepted)

x = 0.8*(accepted)

(accepted) = x/0.8 = x*10/8 = 1.25x.

Answer: D.
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AndySams
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  11 Oct 2019, 05:25
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Picking numbers would be a good way to solve this problem:

Let's say the number of students desired 'x' is equal to 100
20% of the students who are accepted will not attend. So only 80% of the students who are accepted will attend.

So we can form the question, 100 is 80% of what number:

8y/10=100
8y=1000
y=125
This tells us that 125 students need to be accepted so that there are 100 students enrolled

125=1.25(100)
Since we know x=100 then
1.25x=125

Answer choice D
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Abhishek009
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  11 Oct 2019, 07:58
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targetbusiness wrote:
A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A. 1.05x
B. 1.1x
C. 1.2x
D. 1.25x
E. 1.8x


If 80 students attends the college then 100 students are enrolled.
If 1 students attends the college then \(\frac{100}{80}\)students are enrolled.
If x students attends the college then \(\frac{100*x}{80} = 1.25x\)students are enrolled.

ANswer must be (D)
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BrentGMATPrepNow
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  31 Jan 2020, 07:53
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targetbusiness wrote:
A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A. 1.05x
B. 1.1x
C. 1.2x
D. 1.25x
E. 1.8x


20 percent of the students who are accepted will not attend the college
In other words, 80 percent of the students who are accepted WILL ATTEND the college.
In other words, 4/5 of the students who are accepted WILL ATTEND the college.
We can write (4/5)(# accepted) = # who attend

Let x = # of students who attend.
We get the equation: (4/5)(# accepted) = x
Multiply both sides by 5/4 to get: # accepted = (5/4)x
Rewrite as: # accepted = 1.25x

Answer: D

Cheers,
Brent
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ScottTargetTestPrep
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  01 Mar 2020, 13:35
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targetbusiness wrote:
A college admissions officer predicts that 20 percent of the students who are accepted will not attend the college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A. 1.05x
B. 1.1x
C. 1.2x
D. 1.25x
E. 1.8x


We can let y = the number of students that should be accepted to achieve a planned enrollment of x students. We predict that 80% of the students who are accepted will attend the college.Thus, we have:

0.8y = x

y = x/0.8 = 10x/8 = 1.25x

Answer: D
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  17 May 2022, 16:06
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Remember: 20% down + 25% up = 1. Clear Answer but found this shortcut better
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Re: A college admissions officer predicts that 20 percent of the students [#permalink] New post  28 May 2023, 08:35
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